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wariber [46]
3 years ago
8

The difference between the formula you just wrote out and the molecular formula of compound E is one atom. That atom is part of

the functional group that also acounts for the singlet at 5.4 ppm in the 1H NMR spectrum. What is the name of that functional group?
Chemistry
1 answer:
katovenus [111]3 years ago
5 0

Answer: Hydroxyl group -OH

Explanation:

This is because the Hydroxyl group has a single atom which can indicate a singlet on the proton Nmr analysis and the value for -OH is around 4 - 5 ppm as well making the unknown functional group to be likely Hydroxyl group

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What is the mass of 4.56 moles of copper (ii) fluoride​
musickatia [10]

Answer:

463.0 g.

Explanation:

  • We can use the following relation:

<em>n = mass/molar mass.</em>

where, n is the mass of copper(ii) fluoride​ (m = 4.56 mol),

mass of copper(ii) fluoride​ = ??? g.

molar mass of copper(ii) fluoride​ = 101.543 g/mol.

∴ mass of copper(ii) fluoride​ = (n)(molar mass) = (4.56 mol)(101.543 g/mol) = 463.0 g.

7 0
2 years ago
Please help: How do oxidation reactions help people with diabetes monitor their blood glucose levels? Thank you!!!
solong [7]

Answer:-

People with diabetes must monitor their blood glucose levels constantly.

Blood glucose levels are nowadays measured by the help of enzyme glucose oxidase. The enzyme glucose oxidase catalyzes the oxidation of glucose to gluconic acid.

By this way all of the glucose is measured at one time. At the same time hydrogen peroxide is produced.

The hydrogen peroxide reacts with a second color producing chemical. The concentration of the glucose can be related to the intensity of color produced

8 0
3 years ago
Some SbCl5 is allowed to dissociate into SbCl3 and Cl2 at 521 K. At equilibrium, [SbCl5] = 0.195 M, and [SbCl3] = [Cl2] = 6.98×1
Brilliant_brown [7]

Answer:

a) The equilibrium will shift in the right direction.

b) The new equilibrium concentrations after reestablishment of the equilibrium :

[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M

[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

Explanation:

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On increase in amount of reactant

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of SbCl_5 is  increasing .So, the equilibrium will shift in the right direction.

b)

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

Concentration of SbCl_5  = 0.195 M

Concentration of SbCl_3  = 6.98\times 10^{-2} M

Concentration of Cl_2  = 6.98\times 10^{-2} M

On adding more [SbCl_5 to 0.370 M at equilibrium :

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

Initially

0.370 M         6.98\times 10^{-2}M    

At equilibrium:

(0.370-x)M   (6.98\times 10^{-2}+x)M  

The equilibrium constant of the reaction  = K_c

K_c=2.50\times 10^{-2}

The equilibrium expression is given as:

K_c=\frac{[SbCl_3][Cl_2]}{[SbCl_5]}

2.50\times 10^{-2}=\frac{(6.98\times 10^{-2}+x)M\times (6.98\times 10^{-2}+x)M}{(0.370-x) M}

On solving for x:

x = 0.0233 M

The new equilibrium concentrations after reestablishment of the equilibrium :

[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M

[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

3 0
3 years ago
Which elements have the quantum numbers (4,3,-2,+1/2) and (5,2,-1,-1/2)
nikklg [1K]

The elements are samarium (Sm) and silver (Ag).  

<em>Quantum numbers (4,3,-2,+½)  </em>

<em>n</em> = 4: Principal quantum number = 4.  

<em>l</em> = 3: Element has 4f electrons  

It is <em>conventional</em> to list quantum numbers in decreasing order.  

<em>Hund’s rule </em>states that all the orbitals must be half-filled with electrons having the same spin before any can receive a second electron.  

We get the following table:  

<u>Element </u><em><u>n</u></em><u> </u><em><u>l</u></em><u>   </u><em><u>m</u></em><u>ₗ </u><em><u>m</u></em><u>ₛ</u>  

    La      4 3   3 +½  

    Ce     4 3   2 +½  

    Pr      4 3   1  +½  

    Nd    4 3   0 +½  

    Pm   4 3  -1   +½  

    Sm   4 3 -2 +½  

The element is samarium, Sm.  

<em>Quantum numbers (5,2,-1,-½)  </em>

<em>n</em> = 5: Principal quantum number = 5.  

<em>l</em> = 2: Element has <em>5d</em> electrons  

We get the following table:  

<u>Element </u><em><u>n</u></em><u>  </u><em><u>l m</u></em><u>ₗ mₛ</u><em><u>  </u></em>

<em>  </em>   Y       5<em> </em>2  2 +½  

    Zr      5 2  1 +½  

    Nb    5 2  0 +½  

    Mo   5 2  -1 +½  

    Tc    5 2  -2 +½  

    Ru   5 2   2  -½  

    Rh   5 2   1   -½  

    Pd   5 2   0  -½  

    Ag   5 2  -1  -½  

The element is silver, Ag.

<em>Note</em>: These assignments assume that there are <em>no exceptions</em> in the Periodic Table.

7 0
3 years ago
Which is not a compound? a)Gold b)water c)sugar D)silicon dioxide
sweet [91]
Gold is an element. Water is made from hydrogen and oxygen, and silicon dioxide is an oxide of silicon, consisting of <span> two oxygen atoms and one silicon</span>
8 0
3 years ago
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