All categories

3 years ago

How can a rock form by evaporation?What type of rock is it

2 answers:

5 0

Crystsals can precipitate out of solution when some of the solvent is evaporated. For example, if you have sodium chloride in solution and you evaporate out the water some sodium chloride crystals will form. I hope this helps. Let me know if anything is unclear.

const2013 [10]3 years ago

5 0

<span>idk but Metamorphic Rocks</span>

You might be interested in

Which one is a true statement about endothermic reactions? A. I need you from an outside source is continuously being added. B.

tekilochka [14]

Correct answer: "A. Energy from an outside source is continuously being added."
An endothermic reaction is a reaction that is characterised by the system absorbing energy from its surroundings. That energy is usually in heat form. For example, when mixing water<span> with potassium chloride, this reaction will absorb heat and the container will feel cold - endothermic reaction.</span>

7 0

3 years ago

Read 2 more answers

The agent of mechanical weathering in which rock is worn away by the grinding action of other rock particles is call

Igoryamba

Physical weathering

3 0

3 years ago

Chlorine is a very reactive non-metals. Why

Vadim26 [7]

Answer:

Chlorine is a very reactive non metals because this element don't form any known chemical compound.

Explanation:

Chlorine atoms have a lot of valance electrons without being complete on its own, so it has a greater need to seek it's conjugates. That's called electronegativity. Halogens are highly reactive because of their electronegativity.

3 0

3 years ago

Which of the following BEST supports the Big bang theory of the origin of the universe?

inysia [295]

Answer: first one

Explanation:

7 0

3 years ago

A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________

gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

Average velocities of gases can be expressed as root-mean-square averages. (V rms)

$\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}$

R = gas constant, T = temperature, Mm = molar mass of the gas particles

From the question

R = 8,314 J / mol K

T = temperature

Mm = molar mass, kg / mol

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

$\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s$

b. the effusion rates of two gases = the square root of the inverse of their molar masses:

$\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }$

M₁ = molar mass sulfur dioxide = 64

M₂ = molar mass nitrogen triodide = 395

$\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5$

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

4 0

3 years ago