Answer: Ethyl Ethanoate can be used as a developing solvent. It’s safer.
Explanation:Di ethyl ether should be carefully used because it’s highly flammable and intoxicating when inhaled and can cause explosions because of its high reactivity to air and light.
Statement that when two elements combine with each other to from more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.
Answer= C) CN contains a covalent bond.
Answer: The order with respect to 
is 1.
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
![Rate=k[NH_4^+]^x[NO_2^-]^y](https://tex.z-dn.net/?f=Rate%3Dk%5BNH_4%5E%2B%5D%5Ex%5BNO_2%5E-%5D%5Ey)
k= rate constant
x = order with respect to
y = order with respect to A
n = x+y = Total order
From trial 1: ![3.2\times 10^{-3}=k[0.0100]^x[0.200]^y](https://tex.z-dn.net/?f=3.2%5Ctimes%2010%5E%7B-3%7D%3Dk%5B0.0100%5D%5Ex%5B0.200%5D%5Ey)
(1)
From trial 2: ![6.4\times 10^{-3}=k[0.0200]^x[0.200]^y](https://tex.z-dn.net/?f=6.4%5Ctimes%2010%5E%7B-3%7D%3Dk%5B0.0200%5D%5Ex%5B0.200%5D%5Ey)
(2)
Dividing 2 by 1 :![\frac{6.4\times 10^{-3}}{3.2\times 10^{-3}}=\frac{k[0.0100]^x[0.2000]^y}{k[0.0200]^x[0.200]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B6.4%5Ctimes%2010%5E%7B-3%7D%7D%7B3.2%5Ctimes%2010%5E%7B-3%7D%7D%3D%5Cfrac%7Bk%5B0.0100%5D%5Ex%5B0.2000%5D%5Ey%7D%7Bk%5B0.0200%5D%5Ex%5B0.200%5D%5Ey%7D)
therefore x= 1
Thus order with respect to is 1.
5.451 X 10³ kg of sodium carbonate must be added to neutralize 5.04×103 kg of sulfuric acid solution.
<u>Explanation</u>:
- Sodium carbonate is used to neutralized sulfuric acid, H₂SO₄. Sodium carbonate is the salt of a strong base (NaOH) and weak acid (H₂CO₃). The balanced chemical reaction for neutralization is as follows:
Na₂CO₃ + H₂SO₄ ----> Na₂SO₄ + H₂CO₃
- From a balanced chemical equation, it is clear that one mole of Na₂CO₃ is required to neutralize one mole of H₂SO₄.
- Molar mass of Na₂CO₃= 106 g/mol = 0.106 kg/mol and Molar mass of H₂SO₄= 98 g/mol = 0.098 kg/mol.
- To neutralize 0.098 kg of H₂SO₄ amount of Na₂CO₃ required is 0.106 kg, so, To neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ required is = 5.451 X 10³ kg.
