Answer:
See explanation
Explanation:
The magnetic force is
F = qvB sin θ
We see that sin θ = 1, since the angle between the velocity and the direction of the field is 90º. Entering the other given quantities yields
F
=
(
20
×
10
−
9
C
)
(
10
m/s
)
(
5
×
10
−
5
T
)
=
1
×
10
−
11
(
C
⋅
m/s
)
(
N
C
⋅
m/s
)
=
1
×
10
−
11
N
Technician is correct sorry if im wronghg
Answer:
V = 0.30787 m³/s
m = 2.6963 kg/s
v2 = 0.3705 m³/s
v2 = 6.017 m/s
Explanation:
given data
diameter = 28 cm
steadily =200 kPa
temperature = 20°C
velocity = 5 m/s
solution
we know mass flow rate is
m = ρ A v
floe rate V = Av
m = ρ V
flow rate = V =
V = Av = ![\frac{\pi}{4} * d^2 * v1](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2A%20d%5E2%20%2A%20v1)
V = ![\frac{\pi}{4} * 0.28^2 * 5](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2A%200.28%5E2%20%2A%205)
V = 0.30787 m³/s
and
mass flow rate of the refrigerant is
m = ρ A v
m = ρ V
m =
= ![\frac{0.30787}{0.11418}](https://tex.z-dn.net/?f=%5Cfrac%7B0.30787%7D%7B0.11418%7D)
m = 2.6963 kg/s
and
velocity and volume flow rate at exit
velocity = mass × v
v2 = 2.6963 × 0.13741 = 0.3705 m³/s
and
v2 = A2×v2
v2 = ![\frac{v2}{A2}](https://tex.z-dn.net/?f=%5Cfrac%7Bv2%7D%7BA2%7D)
v2 = ![\frac{0.3705}{\frac{\pi}{4} * 0.28^2}](https://tex.z-dn.net/?f=%5Cfrac%7B0.3705%7D%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2A%200.28%5E2%7D)
v2 = 6.017 m/s