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kati45 [8]
3 years ago
12

For an isolated system, the sum of the kinetic and potential energies

Physics
2 answers:
pickupchik [31]3 years ago
5 0
I think it B I hope this help
Elenna [48]3 years ago
4 0
I am pretty sure the answer to your question is B
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A golf club exerts an average horizontal force of 1000 n on a 0.045 -kg golf ball that is initially at rest on the tee. the club
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The impulse (the variation of momentum of the ball) is related to the force applied by
\Delta p = F \Delta t
where \Delta p is the variation of momentum, F is the intensity of the force and \Delta t is the time of application of the force. 
Using F=1000 N and \Delta t = 1.8 ms=1.8 \cdot 10^{-3}s, we can find the variation of momentum:
\Delta p = (1000 N)(1.8 \cdot 10^{-3} s)=1.8 kg m/s

This \Delta p can be rewritten as
\Delta p = p_f - p_i = mv_f - mv_i
where p_f and p_i are the final and initial momentum. But the ball is initially at rest, so the initial momentum is zero, and
\Delta p = mv_f
from which we find the final velocity of the ball:
v_f =  \frac{\Delta p }{m}= \frac{1.8 kg m/s}{0.045 kg}=  40 m/s
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