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son4ous [18]
4 years ago
9

Light passes straight through two polarizing filters in which the axis of polarization of the second filter is rotated 45 degree

s compared to the first filter. How does the light that passes through the second filter compare to the light that passes through the first filter??
Physics
1 answer:
SIZIF [17.4K]4 years ago
4 0

Answer: If the second polarizing filter is rotated by 45°, only the component (parts of the light beam) of the light parallel to the second filter’s axis is passed.

Explanation: Polarization is the process of converting unpolarized light to polarized light.

Polarized light waves are light waves travel in a single plane.

If two polarizing filters are applied to a light wave,

-If the axes of the first and second filters are aligned in a parallel form, it would cause all of the polarized light passed by the first filter to also pass by the second.

- If the second polarizing filter is rotated by an angle of about 45°, only the parts of the light beam parallel to the second filter’s axis is passed.

- When the axes of the polarization filter are perpendicular, no light is passed by the second filter.

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For 6 its D

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3 years ago
Question 10 of 34
labwork [276]

Julia walks from the park, which is six blocks east of her house, to the store, which is three blocks east of her house. Julia walks for 5 minutes. This walk's average speed will be 1.2 blocks per minute. Option B is correct.

<h3>What is displacement?</h3>

Displacement is defined as the shortest distance between the two points. Distance is the horizontal length covered by the body. While displacement is the shortest distance between the two points.

Displacement is a vector quantity .its unit is m.

The average velocity on this walk will be;

\rm v_{avg}= \frac{d}{t} \\\\ \rm v_{avg}= \frac{6 \ block+ 3 \ block }{5 \ minute } \\\\ v_{avg}=1.4  \ block /min

Hence option B is correct.

To learn more about displacement refer to the link; brainly.com/question/10919017

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3 0
2 years ago
Monochromatic light is incident on a pair of slits that are separated by 0.220 mm. The screen is 2.60 m away from the slits. (As
Naddik [55]

Answer:

a

   \lambda = 1.667 nm

b

     \theta  =  0.8681^o

Explanation:

From the question we are told that

   The distance of separation is d  =  0.220 \ mm  =  0.00022 \ m

    The  is distance of the screen from the slit is  D   =  2.60 \ m

    The distance between the central bright fringe and either of the adjacent bright   y  =  1.97 cm  =  1.97 *10^{-2}\ m

Generally  the condition for constructive interference is  

      d sin \tha(\theta ) =  n \lambda

From the question we are told that small-angle approximation is valid here.

So    sin (\theta ) = \theta

=>        d \theta  =  n \lambda

=>        \theta =  \frac{n *  \lambda }{d }

Here n is the order of maxima and the value is  n =  1 because we are considering the central bright fringe and either of the adjacent bright fringes

Generally the distance between the central bright fringe and either of the adjacent bright  is mathematically represented as

         y  =  D * sin (\theta )

From the question we are told that small-angle approximation is valid here.

So

       y  =  D * \theta

=>   \theta  =  \frac{ y}{D}

So

     \frac{n *  \lambda }{d } = \frac{y}{D}

     \lambda =\frac{d * y }{n * D}

substituting values

       \lambda =  \frac{0.00022 * 1.97*10^{-2} }{1 * 2.60 }

        \lambda = 1.667 *10^{-6}

        \lambda = 1.667 nm

In the b part of the question we are considering the next set of bright fringe so  n=  2

    Hence

     dsin (\theta ) =  n \lambda

    \theta  =  sin^{-1}[\frac{ n  *  \lambda }{d} ]

    \theta  =  sin^{-1}[\frac{ 2  *  1667 *10^{-9}}{ 0.00022} ]

    \theta  =  0.8681^o

7 0
4 years ago
If the mass of an object is 176 and Net force is 50, what would be the Acceleration?
pochemuha

Answer:

0.28m/s²

Explanation:

Force = mass•acceleration

F = m•a

50 = 176•a Divide both sides by 176:

50/176 = a ≈ 0.28 m/s²

6 0
3 years ago
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