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yanalaym [24]
3 years ago
5

Carbon dioxide is a...

Chemistry
1 answer:
Marina86 [1]3 years ago
5 0

Answer: Option B) Pure Substance &

Compound

Explanation:

Carbon dioxide is a compound because it is formed when one carbon atom and two oxygen atoms chemically combined together.

C(s) + O2(g) ---> CO2(g)

Also, CO2 is a pure substance because it is natural and cannot be broken down easily or separated by physical methods.

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Which of these contains generic material but is not classified as living?
denis-greek [22]
Viruses are not classified as being alive in because of the fact that they can't reproduce.
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1. Name the compound present in a sample of dry air.
aev [14]

Answer:

not air

Explanation:

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7 0
2 years ago
Terry, a student, performs a titration. He completes these steps as part of his titration procedure: 1. He cleans and rinses a b
Contact [7]

Answer:

D

Explanation:

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3 years ago
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5. A beam of photons with a minimum energy of 222 kJ/mol can eject electrons from a potassium surface. Estimate the range of wav
torisob [31]

Answer: The range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

Explanation:

Given: 222 kJ/mol (1 kJ = 1000 J) = 222000 J

Formula used is as follows.

E = \frac{hc}{\lambda}

where,

E = energy

h = Planck's constant = 6.625 \times 10^{-25} Js

c = speed of light = 3 \times 10^{8} m/s

Substitute the values into above formula as follows.

E = \frac{hc}{\lambda}\\222000 J = \frac{6.625  \times 10^{-34}Js \times 3 \times 10^{8} m/s}{\lambda}\\\lambda = 8.953 \times 10^{21} m

Thus, we can conclude that the range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

7 0
3 years ago
30g of naoh is dissolved in 1.5 liter solution the active mass of naoh is?
Pepsi [2]

Answer:

0.5mol/L

Explanation:

First, let us calculate the number of mole NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the question = 30g

Number of mole = Mass /Molar Mass

Number of mole = 30/40 = 0.75mol

Volume = 1.5L

Active mass = mole/Volume

Active mass = 0.75mol/1.5L

Active mass = 0.5mol/L

7 0
3 years ago
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