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3 years ago

Net Ionic Equation of potassium phosphate (aq) + barium chloride (aq) --> ?

Chemistry

1 answer:

ivolga24 [154]3 years ago

4 0

The answer would be B since it forms a solid

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22. Naturally occurring hydrogen consists of three isotopes, hydrogen-1 (1.07 u)

astra-53 [7]

Answer:

The answer to your question is: a. Hydrogen-1

Explanation:

Hydrogen-1 (1.07 u)

Hydrogen-2 (2.02 u)

Hydrogen-3 (3.01 u)

Periodic table says that H has an atomic mas of 1.008

Then, the reported atomic mass is closer to the mass of the smaller isotope, so Hydrogen-1 must be present in larger percentage.

6 0

3 years ago

A 60g sample of tetraethyl lead, a gasoline additive, is found to contain 38.43g lead, 17.83g carbon and 3.74g hydrogen. Determi

anastassius [24]

Answer:

Empirical formula (which matches the molecular formula) is = PbC₈H₂₀

Explanation:

Our sample: 60 g of tetraethyl lead

In order to determine the compound empirical formula we need the centesimal composition:

(Mass of element / Total mass) . 100 =

(38.43 g lead / 60g ) . 100 = 64.05%

(17.83 g C / 60g) . 100 = 29.72%

(3.74 g H / 60g) . 100 = 6.23 %

These % are the mass of the elements in 100 g of compound. Let's find out the moles of them:

64.05 g / 207.2 g/mol = 0.309 moles

29.72 g / 12 g/mol = 2.48 moles

6.23 g/ 1 g/mol = 6.23 moles

Next, we divide the moles, by the lowest value of them (0.309)

0.309 / 0.309 = 1 mol Pb

2.48 / 0.309 = 8 mol C

6.23 / 0.309 = 20 mol H

There, we have our formula PbC₈H₂₀

6 0

3 years ago

Determine the oh of a solution that is 0.220 m in hco3

ICE Princess25 [194]

Answer : The hydroxide ion concentration of a solution is, $5\times 10^{-14}$

Explanation :

As we know that $HCO_3^-$ dissociates in water to give hydrogen ion $(H^+)$ and carbonate ion $(CO_3^{2-})$ .

As, 1 mole of $HCO_3^-$ dissociates to give 1 mole of hydrogen ion $(H^+)$

Or, 1 M of $HCO_3^-$ dissociates to give 1 M of hydrogen ion $(H^+)$

So, 0.200 M of $HCO_3^-$ dissociates to give 0.200 M of hydrogen ion $(H^+)$

Now we have to calculate the hydroxide ion concentration.

As we know that:

$[H^+][OH^-]=1\times 10^{-14}$

$0.200\times [OH^-]=1\times 10^{-14}$

$[OH^-]=5\times 10^{-14}$

Therefore, the hydroxide ion concentration of a solution is, $5\times 10^{-14}$

6 0

3 years ago

If you are given 1.709 moles of solute, and you dilute it to make 2.10 liters of solution, what is the resulting molarity (M)? (

azamat

Moles/MxL

1.709moles/2.10L =<span>0.814M</span>

4 0

3 years ago

A 5.00 g piece of metal is heated to 100.0oC, then placed in a beaker containing 20.0 g of water at 10.0oC. The temperature of t

Dominik [7]

The metal is 6 a 5.00 g piece of metal is heated to 100. Then places in a beaker containing 20.

3 0

3 years ago