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tatuchka [14]
3 years ago
6

Given the equation: 2Na + 2H2O → 2NaOH + H2 Which substance in this equation is a binary compound?

Chemistry
2 answers:
Blababa [14]3 years ago
8 0
By the definition of a binary compound, the answer is NaOH.
Leto [7]3 years ago
6 0

Answer: In the following equation, H_2O is considered as a binary compound.

Explanation: A binary compound is considered as a compound having 2 elements only. In the following chemical equation:

2Na+2H_2O\rightarrow 2NaOH+H_2

There are 2 compounds present because compound is defined as the chemical combination of two or more elements in a fixed ratio.

In the equation, compounds are: H_2O and NaOH

H_2O consists of 2 elements which are hydrogen and oxygen and hence is considered as a binary compound.

NaOH consists of 3 elements which are sodium, hydrogen and oxygen and hence, cannot be considered as a binary compound.

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Calculate the equilibrium constant for the reaction: 2 Cr + 3 Pb2+ ----> 3 Pb + 2 Cr3+ at 25oC. Eocell = 0.61 V
sattari [20]

Answer:

The value is  K  =  8*10^{61}

Explanation:

From the question we are told that

    The equation is  2 Cr  +  3Pb^{2+} \to 3Pb + 2Cr^{3+}

     The  temperature is  T = 25^oC =  298 K   [room  \ temperature ]

     The  emf at standard condition is  E^o_{cell}  =  0.61 \  V

Generally at the cathode

      3Pb^{2+}(aq) + 6 e- --> 3Pb(s)

  At the anode

      2Cr^{3+} + 6e^- \to  2Cr

Generally for an  electrochemical reaction, at room temperature the Gibbs free energy is mathematically represented as  

       G =  n*  F *  E^o_{cell}

Here  n  is  the no of electron  with value n = 6

       F  is  the Faraday's constant with value 96487 J/V

  =>   G =  6  * 96487 *  0.61

  =>   G = 3.5 *10^{5} \  J

This Gibbs free energy can also be represented mathematically as

       G =  RTlogK

Here  R  is the cell constant with value 8.314J/K

           K is the equilibrium constant

From above

=>  K  =  antilog^{\frac{G}{ RT} }

Generally  antilog =  2.718

=>K  =  2.718^{\frac{3.5 *10^5}{ 8.314* 298} }

=>   K  =  8*10^{61}

       

         

       

         

6 0
3 years ago
How many kilograms of gasoline fill a 12.0-gal gas tank
Sergeu [11.5K]

Answer:

29.98kg

Explanation:

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8 0
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jeka57 [31]

Answer: oxygen

Explanation:

4 0
3 years ago
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T = 20 %  : 20 / 100 = 0.2

m1 = solute 

m2 = Solvent

T = m1 / m1 + m2

0.2 = 500 g / 500 g + m2

0.2 * ( 500 + m2 ) = 500

0.2 * 500 + 0.2 m2 = 500

100 + 0.2 m2 = 500

0.2 m2 = 500 - 100

0.2 m2 = 400

m2 = 400 / 0.2

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hope this helps!



7 0
3 years ago
A 5.0 milliliter sample of a substance has a mass of 12.5 grams. What is the mass of a 100 milliliter sample of the same substan
exis [7]

Answer:

It sould be 250 grams

Explanation:

4 0
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