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3 years ago

Given the equation: 2Na + 2H2O → 2NaOH + H2 Which substance in this equation is a binary compound?

Chemistry

2 answers:

Blababa [14]3 years ago

8 0

By the definition of a binary compound, the answer is NaOH.

Leto [7]3 years ago

6 0

Answer: In the following equation, $H_2O$ is considered as a binary compound.

Explanation: A binary compound is considered as a compound having 2 elements only. In the following chemical equation:

$2Na+2H_2O\rightarrow 2NaOH+H_2$

There are 2 compounds present because compound is defined as the chemical combination of two or more elements in a fixed ratio.

In the equation, compounds are: $H_2O$ and $NaOH$

$H_2O$ consists of 2 elements which are hydrogen and oxygen and hence is considered as a binary compound.

$NaOH$ consists of 3 elements which are sodium, hydrogen and oxygen and hence, cannot be considered as a binary compound.

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In a galvanic cell, electrons are transferred from one half cell to the other as the redox reaction progresses. what happens in

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The half cell in which the electrode gains electrons is where reduction occurs, and the half cell in which the electrode loses electrons is where oxidation occurs.

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<h3><u>Reduction:</u></h3>

The second half-cell, cathode, which is frequently displayed on a figure's right side. The cathode is where reduction happens. The circuit is completed and current can flow by adding a salt bridge.

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2 years ago

Given the amount of camphor (200mg) we are using in this experiment, please determine how many mg of sodium borohydride to use i

swat32

Answer:

Explanation:

From the given information:

Camphor may be reduced as readily in the presence of sodium borohydride(NaHB4). The resulting compound which is stereoselective requires 1 mole of sodium borohydride (NaHB4) to reduce 1 mole of camphor in this reaction. The reaction is shown below.

Through the reduction process of camphor, the reducing agent can reach the carbonyl face with a one-carbon linkage. The product stereoisomer is known as borneol.

If the molecular weight of camphor = 152.24 g/mol

and it mass = 200 mg

The its no of moles = 200 mg/ 152.24 g/mol

= 1.3137 mmol

Now the amount of the required mmol for NaBH4 to be consumed in the reaction = 5.2 × 1.3137 mmol

= 6.831 mmol

since the molar mass of NaBH4 = 37.83 g/mol

Then, using the same formula:

No of moles = mass/molar mass

mass = No of moles × molar mass

mass = 6.831 mmol × 37.83 g/mol

mass of NaBH4 used = 258.42 mg

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3 years ago

What is the percentage by mass of sulphur in Al2(SO4)3[A12SO4 =<br>342g/mol, S = 32]

valentinak56 [21]

Answer: The percentage by mass of sulphur in $Al_2(SO_4)_3$ is 9.36%

Explanation:

Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.

${\text {Mass percentage}}=\frac{\text {mass of sulphur}}{\text {Total mass}}\times 100\%$

Given: mass of sulphur = 32 g/mol

mass of $Al_2(SO_4)_3$ = 342 g/mol

Putting in the values we get:

${\text {Mass percentage}}=\frac{32g/mol}{342g/mol}\times 100\%=9.36\%$

The percentage by mass of sulphur in $Al_2(SO_4)_3$ is 9.36%

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3 years ago