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nata0808 [166]
3 years ago
6

PLEASE HELP...with single replacement reaction w/ activity series

Chemistry
1 answer:
Blizzard [7]3 years ago
8 0

Answer : The balanced chemical reaction will be:

AuI_4+2Br2\rightarrow AuBr_4+2I_2

Explanation :

Single replacement reaction : A chemical reaction in which the more reactive element replace the less reactive element.

It is represented as,

A+BC\rightarrow AC+B

In this reaction, A is more reactive element and B is less reactive element.

As per question, when gold (IV) iodide react with bromine to give gold (IV) bromide and iodine.

The balanced chemical reaction will be:

AuI_4+2Br2\rightarrow AuBr_4+2I_2

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alisha [4.7K]

Answer: Option (b) is the correct answer.

Explanation:

It is known that metals are the species which readily lose an electron and tend to attain a positive charge.

For example, atomic number of sodium is 11 and its is an alkali metal. It electronic distribution is 2, 8, 1.

And, in order to attain stability it readily loses an electron and thus it become Na^{+} ion.

Also, it is known that species which tend to transfer or donate their valence electrons to other atoms tend to form ionic bond and the compound formed is known as ionic compound.

Therefore, we can conclude that the statement metal atoms held together by ionic bonds best describes a metal solid.

4 0
4 years ago
Question 2
san4es73 [151]

Explanation:

its hard to explain unless we know what the question fully asks..

4 0
3 years ago
Please help!!!!!!!!!!!!!!!!!!!
zimovet [89]

Answer:

Your body cells use the oxygen you breathe to get energy from the food you eat. This process is called cellular respiration. During cellular respiration the cell uses oxygen to break down sugar. Breaking down sugar produces the energy your body needs.

Explanation:

Brainly pls

3 0
3 years ago
For the reaction o(g) + o2(g) → o3(g) δh o = −107.2 kj/mol given that the bond enthalpy in o2(g) is 498.7 kj/mol, calculate the
Aneli [31]
The reaction;
O(g) +O2(g)→O3(g), ΔH = sum of bond enthalpy of reactants-sum of food enthalpy of products.
ΔH = ( bond enthalpy of O(g)+bond enthalpy of O2 (g) - bond enthalpy of O3(g)
-107.2 kJ/mol = O+487.7kJ/mol =O+487.7 kJ/mol +487.7kJ/mol =594.9 kJ/mol
Bond enthalpy (BE) of O3(g) is equals to 2× bond enthalpy of O3(g) because, O3(g) has two types of bonds from its lewis structure (0-0=0).
∴2BE of O3(g) = 594.9kJ/mol
Average bond enthalpy = 594.9kJ/mol/2
=297.45kJ/mol
∴ Averange bond enthalpy of O3(g) is 297.45kJ/mol.
8 0
3 years ago
When 500 g of water is cooled from 80.0°C to 10.0°C, how much heat energy is lost?
vampirchik [111]

I don’t know

Explanation:

6 0
3 years ago
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