Answer:
Jupiter and Saturn
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Answer:
(a) emf = 0.507 V
(b) emf = 0.0507 V
(c) emf = 0.00234 V
Explanation:
Given;
number of turns of the coil, N = 40 turns
diameter of the coil, d = 11 cm
radius of the coil, r = 5.5 cm = 0.055 m
magnitude of the magnetic field, B = 0.4 T
The magnitude of the induced emf is calculated as;
![emf = - N\frac{d\phi}{dt} \\\\where;\\\\\phi \ is \ magnetic \ flux= BA \\\\A \ is the \ area \ of \ the \ coil = \pi r^2 = \pi (0.055)^2 = 0.0095 \ m^2\\\\emf = - N \frac{dB.A}{dt} = -NA\frac{dB}{dt} \\\\emf = -NA\frac{(B_2 - B_1)}{t} \\\\emf = NA \frac{(B_1 - B_2)}{t} \\\\the \ final \ magnetic \ field \ is \ reduced \ to \ zero;\ B_2 = 0\\\\emf = \frac{NAB_1}{t}](https://tex.z-dn.net/?f=emf%20%3D%20-%20N%5Cfrac%7Bd%5Cphi%7D%7Bdt%7D%20%5C%5C%5C%5Cwhere%3B%5C%5C%5C%5C%5Cphi%20%5C%20is%20%5C%20magnetic%20%5C%20flux%3D%20BA%20%5C%5C%5C%5CA%20%5C%20is%20the%20%5C%20area%20%5C%20of%20%5C%20the%20%5C%20coil%20%3D%20%5Cpi%20r%5E2%20%3D%20%5Cpi%20%280.055%29%5E2%20%3D%200.0095%20%5C%20m%5E2%5C%5C%5C%5Cemf%20%3D%20-%20N%20%5Cfrac%7BdB.A%7D%7Bdt%7D%20%3D%20-NA%5Cfrac%7BdB%7D%7Bdt%7D%20%5C%5C%5C%5Cemf%20%3D%20-NA%5Cfrac%7B%28B_2%20-%20B_1%29%7D%7Bt%7D%20%5C%5C%5C%5Cemf%20%3D%20NA%20%5Cfrac%7B%28B_1%20-%20B_2%29%7D%7Bt%7D%20%5C%5C%5C%5Cthe%20%5C%20final%20%5C%20magnetic%20%5C%20field%20%5C%20is%20%5C%20reduced%20%5C%20to%20%5C%20zero%3B%5C%20B_2%20%3D%200%5C%5C%5C%5Cemf%20%3D%20%5Cfrac%7BNAB_1%7D%7Bt%7D)
(a) when the time, t = 0.3 s
![emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{0.3} = 0.507 \ V](https://tex.z-dn.net/?f=emf%20%3D%20%5Cfrac%7BNAB_1%7D%7Bt%7D%20%3D%20%5Cfrac%7B40%5Ctimes%200.0095%5Ctimes%200.4%7D%7B0.3%7D%20%3D%200.507%20%5C%20V)
(b) when the time, t = 3.0 s
![emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{3} = 0.0507 \ V](https://tex.z-dn.net/?f=emf%20%3D%20%5Cfrac%7BNAB_1%7D%7Bt%7D%20%3D%20%5Cfrac%7B40%5Ctimes%200.0095%5Ctimes%200.4%7D%7B3%7D%20%3D%200.0507%20%5C%20V)
(c) when the time, t = 65 s
![emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{65} = 0.00234 \ V](https://tex.z-dn.net/?f=emf%20%3D%20%5Cfrac%7BNAB_1%7D%7Bt%7D%20%3D%20%5Cfrac%7B40%5Ctimes%200.0095%5Ctimes%200.4%7D%7B65%7D%20%3D%200.00234%20%5C%20V)
Answer:
Metals produce electrons ( photoelectrons ) when exposed to light.
Explanation:
These photoelectrons produce photocurrent and this was proved by Eistein illustration of photocurrent and stopping potential.
2.1 x 102
Is the correct solution for this problem