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3 years ago

Cosmic microwave background radiation found uniformly spread throughout the universe is supposed to be _____.

Chemistry

2 answers:

slava [35]3 years ago

7 0

Answer:

Option (B)

Explanation:

The Cosmic Microwave Background (CMB) radiations are defined as one type of electromagnetic radiation which is generated after the big bang explosion. These are considered to be the remnant radio waves that are equally distributed in all the direction in space. These are not directly visible but their presence can be detected with the help of various detecting devices and instruments. One of the important significance of this wave is that it describes that the universe is constantly expanding.

Thus, these are the radio waves coming from distant galaxies.

Hence, the correct answer is option (B).

Dmitry [639]3 years ago

3 0

B. Radio waves from distant galaxies

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A chemist forms 16.6 g of potassium iodide by combining 3.9 g of potassium with 12.7 g of iodine. Show that these results are co

bezimeni [28]

3.9 g + 12.7 g = 16.6 g

The sum of the masses of potassium and iodine equals the mass of the product, potassium iodide. The results are consistent with he law of conservation of mass.

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2 years ago

Can someone help me? It needs to have a diagram that has arrows.

daser333 [38]

Answer: The enthalpy change for formation of butane is -125 kJ/mol

Explanation:

The balanced chemical reaction is,

$C_4H_{10}(g)+\frac{13}{2}O_2(g)\rightarrow 4CO_2(g)+5H_2O(l)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f{products}]-[n\times H_f{reactants}]$

Putting the values we get :

$\Delta H=[4\times H_f_{CO_2}+5\times H_f_{H_2O}]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times H_f_{O_2}]$

$-2877=[(4\times -393)+(5\times -286)]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times 0]$

$H_f_{C_4H_{10}=-125kJ/mol$

Thus enthalpy change for formation of butane is -125 kJ/mol

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3 years ago

What is the ratio of effusion rates of krypton and neon at the same temperature and pressure?

egoroff_w [7]

The formula we use would be the graham's law. We do as follows:

E_Kr / E_Ne = sqrt ( M_Ne / M_Kr)

= sqrt ( 20.1797 g/mol / 83.798 g/mol ) 
= sqrt (0.24081) 
= 0.4907

Hope this answers the question. Have a nice day.

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2 years ago

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Determine the mass, in grams, of 0.350 moles of s (1 mol of s has a mass of 32.07 g).

hram777 [196]

Answer:

11.22 gm

Explanation:

32.07 gm / mole * .350 mole = 11.22 gm

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1 year ago

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vovikov84 [41]

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3 years ago