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hodyreva [135]
3 years ago
9

Two Jupiter-size planets are released from rest 1.40×10^11 m apart.. What are their speeds as they crash together?

Physics
1 answer:
Sonbull [250]3 years ago
7 0
M₁ = mass of planet #1 
M₂ = mass of planet #2 
M = total mass 
R₁ = radius of planet #1 
R₂ = radius of planet #2 
d₁ = initial distance between planet centers 
d₂ = final distance between planet centers 
a = semimajor axis of plunge orbit 
v₁ = relative speed of approach at distance d₁ 
v₂ = relative speed of approach at distance d₂ 

M₁ = M₂ = 1.8986e27 kilograms 
M = M₁ + M₂ = 3.7972e27 kg 
G = 6.6742e-11 m³ kg⁻¹ sec⁻² 
GM = 2.5343e17 m³ sec⁻² 
d₁ = 1.4e11 meters 
a = d₁/2 = 7e10 meters 
R₁ = R₂ = 7.1492e7 meters 
d₂ = R₁ + R₂ = 1.42984e8 meters 
v₁ = 0 
v₂ = √[GM(2/d₂−1/a)] 
<span>
v₂ = 59508.4 m/s </span>
<span>
The time to fall is 1337.7 days

.</span>I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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The specific heat of fat is roughly 1,700 J/(kgoC) whereas that for water is around 4200 J/(kgoC). A 0.63 kg solution of lipids
BartSMP [9]

Answer:

the mass of the lipid content, to the nearest hundredth of a kg, in this solution =0.46 kg

Explanation:

Total heat content of the fat = heat content of water +heat content of the lipids

Let it be Q

the Q= (mcΔT)_lipids + (mcΔT)_water

total mass of fat  M= 0.63 Kg

Q= heat supplied = 100 W in 5 minutes

ΔT= 20°C

c_lipid= 1700J/(kgoC)

c_water= 4200J/(kgoC)

then,

100\times5\times60= m(1700)20+(0.63-m)(4200)20

solving the above equation we get

m= 0.46 kg

the mass of the lipid content, to the nearest hundredth of a kg, in this solution =0.46 kg

3 0
3 years ago
It is essential to behave appropriately on social media and be _______ when you post anything.
Firdavs [7]

Answer:

I would say be Mindful.

Explanation:

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5 0
2 years ago
A stable, binary ionic compound exists where the cation (A) has a charge twice in magnitude than that of the anion (X). What wou
svetlana [45]
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3 years ago
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A laser source has a bandwidth of 30GHz (a) Calculate the coherence length of the source b) What is the time separation of secti
abruzzese [7]

Explanation:

It is given that,

Bandwidth of a laser source, f=30\ GHz=30\times 10^9\ Hz

(b) Let t is the time separation of sections of sections of the light wave that can still interfere. The time period is given by :

T=\dfrac{1}{f}

T=\dfrac{1}{30\times 10^9}

T=3.33\times 10^{-11}\ s

(a) Let h is the coherence length of the source. It is given by :

l=c\times T

c is the speed of light

l=3\times 10^8\times 3.33\times 10^{-11}

l = 0.0099 m

Hence, this is the required solution.

6 0
2 years ago
The image messed up but you get the point. Don't be mean and just answer to get the points, please and thank you.
Katarina [22]

Answer:

Answer is A, it will pass through to focal point after reflecting.

Explanation:

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