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Novosadov [1.4K]
3 years ago
10

Amy is standing still on the ground; Bill is riding his bicycle at 5 m/s eastward; and Carlos is driving his car at 15 m/s westw

ard. How fast does Bill see Carlos moving and in what direction?
Physics
1 answer:
Solnce55 [7]3 years ago
3 0

Answer:

20 m/s westward

Explanation:

Taking eastward as positive direction, we have:

v_B = +5 m/s is the velocity of Bill with respect to Amy (which is stationary)

v_C = -15 m/s is the velocity of Carlos with respect to Amy

Bill is moving 5 m/s eastward compared to Amy at rest, so the velocity of Bill's reference frame is

v_B = +5 m/s

Therefore, Carlos velocity in Bill's reference frame will be

v_C' = v_C - v_B = -15 m/s - (+5 m/s) = -20 m/s

and the direction will be westward (negative sign).

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Constants Part A wo charged dust particles exert a force of 7.5x102 N n each other What will be the force if they are moved so t
alexandr1967 [171]

Answer:

New force, F'=48\times 10^3\ N

Explanation:

It is given that,

Force acting between two charged particles, F=7.5\times 10^2\ N

We need to find the force if they are moved so they are only one-eighth as far apart.

The force between two charged particles separated at a distance of r is given by :

F=k\dfrac{q_1q_2}{r^2}............(1)

If the charges are one-eighth as far apart then, r' =(1/8)r and new force is given by :

F'=k\dfrac{q_1q_2}{(\dfrac{r}{8})^2}..........(2)

Dividing equation (1) and (2) :

\dfrac{F}{F'}=\dfrac{1}{64}

F'=7.5\times 10^2\ N\times 64

F' = 48000 N

or

F'=48\times 10^3\ N

Hence, this is the required solution.

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3 years ago
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Answer:

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2 years ago
Calculate the wavelengths of the first five emission lines of the Balmer series for hydrogen
In-s [12.5K]

Answer:

Explanation:

The Balmer series in a hydrogen atom relates the possible electron transitions down to the n = 2 position to the wavelength of the emission that scientists observe. In quantum physics, when electrons transition between different energy levels around the atom (described by the principal quantum number, n) they either release or absorb a photon. The Balmer series describes the transitions from higher energy levels to the second energy level and the wavelengths of the emitted photons. You can calculate this using the Rydberg formula.

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2 years ago
Answer it answer it answer it
scoray [572]

Answer: I believe the answer is C. Higher Volume.

Explanation: I apologize if I am incorrect.

4 0
3 years ago
A projectile is shot on level ground with a
erastova [34]

Answer:

time rising = 34 / 9.8 = 3.47 sec

total time in air = 2 * 3.47 sec = 6.94 sec

(time rising must equal time falling)

R = 17 m/s * 6.94 s = 118 m

Can also use range formula

R = v^2 sin (2 theta) / g

tan theta = 34 / 17 = 2

theta = 63.4 deg

2 theta = 126.9 deg

sin 126.9 = .8

v^2 = 17^2 + 34^2 = 1445 m^2/s^2

R = 1445 * .8 / 9.8 = 118 m    agreeing with answer found above

5 0
2 years ago
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