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3 years ago

PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!

Physics

2 answers:

ra1l [238]3 years ago

3 0

Answer:

Explanation:

This is true because culture in Asia focus more on energy that is why we see kung fu and taekwondo etc.

zaharov [31]3 years ago

3 0

Answer:

I say it might be true points go to the person above me if I get it right

Explanation:

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The velocity of a ball changes from ‹ 9, −6, 0 › m/s to ‹ 8.96, −6.12, 0 › m/s in 0.02 s, due to the gravitational attraction of

Alenkasestr [34]

Answer:

a) $a=(-2,-6,0)m/s^2$ , with a magnitude of $6.3m/s^2$

b) $\frac{\Delta p}{\Delta t}=(-0.24,-0.72,0)Kgm/s^2$ , with a magnitude of $0.76Kgm/s^2$

c) $F=(-0.24,-0.72,0)N$ , with a magnitude of $0.76N$

Explanation:

We have:

$v_{ix}=9m/s, v_{iy}=-6m/s, v_{iz}=0m/s\\v_{fx}=8.96m/s, v_{fy}=-6.12m/s, v_{fz}=0m/s\\t=0.02s, m=0.12Kg$

We can calculate each component of the acceleration using its definition $a=\frac{\Delta v}{\Delta t}$

$a_x=\frac{v_{fx}-v_{ix}}{t} = \frac{(8.96m/s)-(9m/s)}{0.02s} =-2m/s^2\\a_y=\frac{v_{fy}-v_{iy}}{t} = \frac{(-6.12m/s)-(-6m/s)}{0.02s} =-6m/s^2\\a_y=\frac{v_{fz}-v_{iz}}{t} = \frac{(0m/s)-(0m/s)}{0.02s} =0m/s^2\\$

The rate of change of momentum of the ball is $\frac{\Delta p}{\Delta t} = \frac{\Delta mv}{\Delta t} = \frac{m\Delta v}{\Delta t} = ma$

So for each coordinate:

$\frac{\Delta p_x}{\Delta t}=-0.24Kgm/s^2\\\frac{\Delta p_y}{\Delta t}=-0.72Kgm/s^2\\\frac{\Delta p_z}{\Delta t}=0Kgm/s^2$

And these are equal to the components of the net force since F=ma.

If magnitudes is what is asked:

$a=\sqrt{a_x+a_y+a_z} =6.3m/s^2\\F=ma=\frac{\Delta p}{\Delta t}=0.76N$

(N and $Kgm/s^2$ are the same unit).

3 0

3 years ago

True or false Mechanical energy is associated only with the motion of an object.

Katyanochek1 [597]

False ,it does not only associate with motion of object

4 0

3 years ago

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If u speed up from rest to 12 m/s in 3 seconds, what is your acceleration

irakobra [83]

4

Just divide 12 by 3, so if it takes 3 seconds, then every second, it goes up 4.

4 0

3 years ago

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The common value for the speed of light in a vacuum is:

OLEGan [10]

The common value for “Speed of light in vacuum” is $\bold{3 \times 10^{8}}$ metre per second.

Answer: Option b

Solution:

Speed of light can be defined as the speed with which light waves propagate in different medium. In vacuum, speed of light is 186,282 miles per second or 299,792 km/s which is rounded off as $3 \times 10^{8} \mathrm{m} / \mathrm{s}$ .

“Speed of light in vacuum” is a universal constant and usually represented by ‘c’. Light waves travels at a speed of $3 \times 10^{8}$ metre per second in vacuum.

5 0

3 years ago

PLEASE HELP AND HURRY

Ahat [919]

Answer:

Explanation:

6 0

3 years ago

Read 2 more answers