I think you can google this because I really don’t know the answer I’m so sorry
Am not really sure but what i see is D
Answer:
(a) 3107.98 J
(b) 14530.6 J
Explanation:
mass, m = 3.56 kg
angular speed, ω = 179 rad/s
Moment of inertia of solid cylinder, I = 1/2 mr^2
where, m is the mass and r be the radius of the cylinder.
(a) radius, r = 0.330 m
I = 0.5 x 3.56 x 0.330 x 0.330 = 0.194 kgm^2
The formula for the rotational kinetic energy is given by
![K = \frac{1}{2}I\omega ^{2}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7DI%5Comega%20%5E%7B2%7D)
K = 0.5 x 0.194 x 179 x 179 = 3107.98 J
(b) radius, r = 0.714 m
I = 0.5 x 3.56 x 0.714 x 0.714 = 0.907 kgm^2
The formula for the rotational kinetic energy is given by
![K = \frac{1}{2}I\omega ^{2}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7DI%5Comega%20%5E%7B2%7D)
K = 0.5 x 0.907 x 179 x 179 = 14530.6 J