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sladkih [1.3K]
3 years ago
12

A negatively charged balloon has 2.6 µc of charge. how many excess electrons are on this balloon? the elemental charge is 1.6 ×

10−19
c. answer in units of electrons.
Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
5 0
The given 2.6 µC of charge is due to a buildup of electrons, each of which has a charge of 1.6 x 10^-19 C. The 2.6 <span>µC is equivalent to 2.6 x 10^-6 C, so we can divide this by the individual charge of an electron:
</span>2.6 x 10^-6 C / 1.6 x 10^-19 (C/electron) = 1.625 x 10^13 electrons
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Physical Meaning of pKa Which of the following aqueous solutions has the lowest pH: 0.1 M HCl; 0.1 M acetic acid (pKa = 4.86); 0
ser-zykov [4K]

Answer:

<em>The solution with the lowest pH is 0.1 M HCl.</em>

Explanation:

Since the three solutions have the same concentration (0,1M) it is only necessary to look at the pKa of each solution.

Also, knowing that a higher pKa means a lower Ka, because pKa = -Log (Ka). Thus, a lower Ka means a lower concentration of protons with a higher pH ( pH = -Log [H+].

The HCl doesn't have a pKa because is a strong acid that dissociates completely. Therefore, this solution produces a lower pH. Looking at the pKa of acetic acid and formic acid solutions, the second with the lowest pH is the formic acid solutions and the higher pH is for the acetic acid solution.

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Given the following: I) N20(g) 1/2 02(g) 2 NO(g) II) N2(g) 02(g) 2 NO(g) Ke= 4.1 x 10-31 Ke= 1.7 x 10-13 Find the value of the e
tresset_1 [31]

Answer:

Answer B) 4.2x10^17

Explanation:

To produce the reaction 3 using reaction 1 and 2 we need to invert the order of the first reaction the second in the same order, as it's shown:

2NO-------->N_2O+1/2O_2 : (reaction 1' :K'_1 =1/K_1=2.4x10^ 3^0)

N_2+O_2-------->2NO: (reaction 2 :K_2 =1.7x10^-^1^3)

____________________________

N_2+1/2O_2-------->N_2O: (reaction 3)

Due to the inversion of the first equation, the equilibrium constant of the new reaction is K1'=1/K1.=2.4x10^30

Finally, the new equilibrium constant K3 is the product of the previous constants:  

K3=K1'*K2=4.2x10^17

6 0
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