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Svetllana [295]
3 years ago
10

Using a force of 28.0 Newton, a student pulls a 70.0 Newton weight along the tabletop for a distance of 15.0 meters in 3.0 secon

ds. Compute the power developed by the student.
Physics
1 answer:
Musya8 [376]3 years ago
8 0

Answer:

140 watt

Explanation:

We are given that

Force applied by student ,F=28 N

Weight pulled  by students=70 N

Displacement,s=15 m

Time=3 s

We have to find the power developed  by the student.

Work done=w=F\times s

Work done by the student=28\times 15=420 J

Power=\frac{work\;done}{time}

Using the formula

Power=\frac{420}{3}=140watt

Hence, the power developed by the students=140 watt

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A proton traveling at 17.6° with respect to the direction of a magnetic field of strength 3.28 mT experiences a magnetic force o
umka2103 [35]

Answer:

a) The proton's speed is 5.75x10⁵ m/s.

b) The kinetic energy of the proton is 1723 eV.  

Explanation:

a) The proton's speed can be calculated with the Lorentz force equation:

F = qv \times B = qvBsin(\theta)     (1)          

Where:

F: is the force = 9.14x10⁻¹⁷ N

q: is the charge of the particle (proton) = 1.602x10⁻¹⁹ C

v: is the proton's speed =?

B: is the magnetic field = 3.28 mT

θ: is the angle between the proton's speed and the magnetic field = 17.6°

By solving equation (1) for v we have:

v = \frac{F}{qBsin(\theta)} = \frac{9.14 \cdot 10^{-17} N}{1.602\cdot 10^{-19} C*3.28 \cdot 10^{-3} T*sin(17.6)} = 5.75 \cdot 10^{5} m/s

Hence, the proton's speed is 5.75x10⁵ m/s.

b) Its kinetic energy (K) is given by:

K = \frac{1}{2}mv^{2}

Where:

m: is the mass of the proton = 1.67x10⁻²⁷ kg

K = \frac{1}{2}mv^{2} = \frac{1}{2}1.67 \cdot 10^{-27} kg*(5.75 \cdot 10^{5} m/s)^{2} = 2.76 \cdot 10^{-16} J*\frac{1 eV}{1.602 \cdot 10^{-19} J} = 1723 eV  

Therefore, the kinetic energy of the proton is 1723 eV.

I hope it helps you!        

3 0
3 years ago
If the IMA of a machine is 2 and the effort force is 50 newtons, then the force applied to the resistance is _____. 48 N 50 N 25
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IMA stands for ideal mechanical advantage, which is the theoretical force amplification factor on an ideal mechanical device free of friction, deformations, etc.


If the applied force (effort) is 50N, then the force applied to the resistance is multiplied by the IMA=2 to get 100N.

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C. those are all metals.
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A physicist found that a force of 1.32 N was measured between two charged spheres. The distance between the spheres was 95 cm. C
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The electric force (and the gravitational force too) is inversely proportional
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In this question, the distance is increased by a factor of  (1.25/0.95) .

So the electric force will change by the factor of  (0.95/1.25)² .

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           (1.32 N) · (0.95/1.25)²  =  0.762... newton   (rounded)
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