Using a force of 28.0 Newton, a student pulls a 70.0 Newton weight along the tabletop for a distance of 15.0 meters in 3.0 secon
1 answer:
Answer:
140 watt
Explanation:
We are given that
Force applied by student ,F=28 N
Weight pulled by students=70 N
Displacement,s=15 m
Time=3 s
We have to find the power developed by the student.
Work done=w=
Work done by the student=
Power=
Using the formula
Power=
Hence, the power developed by the students=140 watt
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Answer:
The second ball lands 1.5 s after the first ball.
Explanation:
Given;
initial velocity of the ball, u = 12 m/s
height of fall, h = 35 m
initial velocity of the second, v = 12 m/s
Time taken for the first ball to land;
determine the maximum height reached by the second ball;
v² = u² -2gh
at maximum height, the final velocity, v = 0
0 = 12² - (2 x 9.8)h
19.6h = 144
h = 144 / 19.6
h = 7.35 m
time to reach this height;
Total height above the ground to be traveled by the second ball is given as;
= 7.35 m + 35m
= 42.35 m
Time taken for the second ball to fall from this height;
total time spent in air by the second ball;
T = t₁ + t₂
T = 1.23 s + 2.94 s
T = 4.17 s
Time taken for the second ball to land after the first ball is given by;
t = 4.17 s - 2.67 s
T = 1.5 s
Therefore, the second ball lands 1.5 s after the first ball.