The normal force acting on the object is 500 N in the upward direction
<u>Explanation:</u>
As George is applying a downward force, the normal force will be in the upward direction. The normal force will be exerted due to the acceleration due to gravity exerted on the object.
So, as per Newton's second law, the normal force acting on the object can be measured by the product of mass of the object and the acceleration due to gravity acting on the object.
But as the acceleration due to gravity is a downward acting acceleration and the normal force is a upward acting force, so the acceleration will be having a negative sign in the formula.
Here, acceleration due to gravity g = -10 m/s² and mass is given as 50 kg, then
Normal force = 50 × (-10) = -500 N
So, the normal force acting on the object is 500 N in the upward direction.
Option (D) is the correct one.
In order to increase the amount of work done, we need to increase the force applied to the object.
Answer:
Torque = 35.60 N.m (rounded off to 3 significant figures.
Explanation:
Given details:
The mass of the rock on the left, ms = 2.25 kg
The total mass of the rocks, mp = 10.1 kg
The distance from the fulcrum to the center of the pile of rocks, rp = 0.360 m
(a) The torque produced by the pile of rock, T = F*rp = m*g*rp
Torque = 9.8*0.360*10.1 = 35.6328
Torque = 35.60 N.m (rounded off to 3 significant figures).
Self productive and it depends on how whom is behaving.
Answer:
option C
Explanation:
given,
Force by the engine on plane in West direction = 350 N
Frictional force on the runway = 100 N in east
force exerted by the wind = 100 N in east
net force and direction = ?
consider west to be positive and east be negative.
when airplane will be moving there will be frictional as well as wind resistance will be acting in opposite direction of airplane
Net force = 350 N - 100 N - 100 N
= 150 N
as our answer comes out to be positive so the airplane will be moving in West
hence, the correct answer is option C
