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Irina18 [472]
3 years ago
9

Blythe and Geoff are ice-skating together. Blythe has a mass of 40 kg and Geoff has a mass of 79 kg. Blythe pushes Geoff in the

chest when both are at rest, causing him to move away at a speed of 5 m/s.

Physics
2 answers:
alexandr1967 [171]3 years ago
6 0

Answer:

Speed of Blythe is 9.8 m/s.

Explanation:

Mass of Blythe =40 kg

Mass of Geoff = 79 kg

Speed = 5 m/s

Suppose, we determine the Blythe's speed after she pushes Geoff

Since, initial momentum is zero final momentum should be zero.

Using momentum of conservation

m_{B}v_{B}+m_{G}v_{G}=0

v_{B}=-\dfrac{m_{G}v_{G}}{m_{B}}

Put the value into the formula

v_{B}=-\dfrac{79\times5}{40}

v_{B}=-9.8\ m/s

Negative sign shows that he move in direction opposite to Geoff.

Hence, Speed of Blythe is 9.8 m/s.

Deffense [45]3 years ago
4 0
9.9 m/s

calculations below 

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Artyom0805 [142]

Answer:

The heat transferred into the system is 183.5 J.

Explanation:

The first law of thermodynamics relates the heat transfer into or out of a system to the change of internal and the work done on the system, through the following equations.

ΔU = Q - W

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ΔU  is the change in internal energy

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Given;

ΔU = 155 J

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Therefore, the heat transferred into the system is 183.5 J.

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3 years ago
Someone help please by providing work and answers please :)
Nastasia [14]
First we gotta use an equation of motion:

d = ut + \frac{1}{2} a {t}^{2}

Our vertical distance d= 100 m, initial vertical speed u = 0 m/s (because velocity is fully horizontal), and vertical acceleration a = 9.8 m/s2 because of gravity. Let's plug it all in!

100 = 0 + \frac{1}{2} (9.8) {t}^{2}

Now we just need to solve for t:

{t}^{2} = \frac{2(100)}{9.8} \\ \\ t = \sqrt{\frac{2(100)}{9.8}}

Hit the calculators, and you'll get 4.5 seconds!
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What will most likely happen if a sound wave moves from the air through a solid?
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A river flows due south with a speed of 2.0 m/s. You steer a motorboat across the river; your velocity relative to the water is
neonofarm [45]

Answer:

a) 25.5°(south of east)

b) 119 s

c) 238 m

Explanation:

solution:

we have river speed v_{r}=2 m/s

velocity of motorboat relative to water is v_{m/r}=4.2 m/s

so speed will be:

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solving graphically

v_{m}=\sqrt{v^2_{r}+v^2_{m/r}}

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c) d=v_{r}t=(2)(119)=238 m

note :

pic is attached

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3 years ago
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andreyandreev [35.5K]

Answer:

Explanation:

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