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amm1812
3 years ago
11

Differentiate between adhesion and cohesion.

Physics
1 answer:
sergiy2304 [10]3 years ago
8 0
<h2>Answer:</h2>

<h2>Cohesion </h2>

Is the attraction that molecules have for others of their same type.

<h2>Adhesion </h2>

Is the attraction that molecules have for others of different type by  intermolecular forces.

A good example of both is water  that can stick to itself through hydrogen bonds (cohesion) and can also stick to a glass due to adhesion.

So, while Cohesion is the force of attraction between adjacent particles within the same body, Adhesion is the interaction between the surfaces of different bodies.

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Which of the following is the correct abbreviated SI unit describing the mass of an object? a. molly
lions [1.4K]

The answer is C I hope this helps

7 0
3 years ago
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A foot is 12 inches and a mile is 5280I ft exactly. A centimeter is exactly 0.01m or mm. Sammy is 5 feet and 5.3tall. what is Sa
julia-pushkina [17]

Answer:

65.3 Inches tall

Explanation:

If Sammy is 5 feet and 5.3 inches tall, we simply need to convert the feet to inches, and sum the remaining inches from his height to determine his overall height in inches.

So, 5 feet = (12 inches/1foot) * (5 feet) = 60 inches

And 60 inches + 5.3 inches = 65.3 inches.

Hence, Sammy is 65.3 inches tall.

Cheers.

4 0
3 years ago
If the speed of a ball increased from 1m/s to 4m/s, by how much would the kinetic energy increase
GREYUIT [131]
In 16 times
KE= o.5 m times V squared
6 0
3 years ago
Match each letter on the left to box on right, need help
svlad2 [7]

Answer:

Acceleration → Change in velocity divided by time.

Proportional → Net force and acceleration

Inversely Proportional → Mass and acceleration

Net force Not Equal to zero → Driving a car up the on-ramp of the freeway

Net force Equal to zero → Driving a car with cruise control on, straight down.

Acceleration → Net force divided by mass

Force → Mass times acceleration.

Explanation:

Below we will explain each choice.

A) Acceleration by means of the following expression of kinematics is defined as the change of velocities in a given time.

a=\frac{v_{f}-v_{o}}{t}

where:

a = acceleration [m/s²]

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

t = time [s]

B)

Newton's Second Law tells us that the sum of forces in a body is equal to the product of mass by acceleration so we have the following expression.

F = m*a

where:

F = force [N] (units of Newtons)

m = mass [kg]

a = acceleration [m/s²]

As we can see in the previous equation The Force is proportional to the acceleration, that is to say, every time the acceleration increases or decreases this same will happen with the force, increases or decreases.

C)

In Newton's second law we see an inversely proportional relationship, which is best seen if we clear the term of acceleration.

a=\frac{F}{m}

In any mathematical expression where a term is in the denominator, we can say that this is inversely proportional to the term to the left of the equal sign.

D)

When a vehicle climbs a hill or climbs a slope, forces such as the weight of the vehicle act in the opposite direction to the movement, so the sum of the forces cannot be equal to zero.

E)

When a vehicle moves on a track at a constant speed that is to say at cruising speed, we say that its acceleration is zero, therefore the sum of the forces acting on the moving vehicle is equal to zero.

F)

Acceleration is defined as the relationship between Force and mass

a =\frac{F}{m}

G)

Force is defined as the product of mass by acceleration.

F = m*a

7 0
4 years ago
What is the change in internal energy (in J) of a system that releases 954 J of thermal energy to its surroundings and has 166 c
Harman [31]

Answer:

259.456 J

Explanation:

Given that,

Work done on the system = 166 cal

The systam releases 954 J of thermal energy to its surroundings

We need to find the change in internal energy. It can be given by using the first law of thermodynamics as follows :

\Delta U=Q-W

W = 166 cal = 694.544 (1cal = 4.184 J)

\Delta U=954-694.544\\\\=259.456\ J

So, the change in internal energy of the system is 259.456 J.

4 0
3 years ago
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