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Vikki [24]
3 years ago
14

An inventor tries to sell you his new heat engine that takes in 40 J of heat at 87°C on each cycle, expels 30 J at 27°C, and doe

s 10 J of work. Would it be wise to invest in this engine?
Engineering
1 answer:
algol133 years ago
5 0

Answer:

NOT WISE

Explanation:

given,

T₁ = 87⁰C  =  273 + 87 = 360 K

T₂ = 27⁰C  =  273 + 27 = 300 K

work output given = 10 J

efficiency will be equal to :

   \eta = 1 - \dfrac{T_2}{T_1}\\\eta = 1 - \dfrac{300}{360}\\\eta = 0.166

output delivery =  η ₓ input

                          =  0.166 ₓ 40  

                          = 6.66 J

hence, the output of new engine  is less than the old one so, investing in new engine will not be feasible.

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Explanation:

Isentropic process is the process in which the entropy of the system remains unchanged. The word isentropic is formed from the combination of the prefix "iso" which means "equal" and the word entropy.

If a process is completely reversible, without the need to provide energy in the form of heat, then the process is isentropic.

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