Answer:
1.25 cm/day
Explanation:
An air thickness , (l) = 0.15 cm
Air Temperature =
Mass Diffusion coefficient (D) =
If the air pressure
We are to determine how fast will the water level drop in a day.
From the property of air at T = 20° C
from saturated water properties.
The mass flow of can be calculated as:
where:
R(constant) = 8.314 kJ/mol.K
Since 1 mole = 18 cm ³ of water
will be:
Again:
Converting the above value to cm/day: we have:
= 1.25 cm/day
∴ the rate at which the water level drop in a day = 1.25 cm/day
they can make objects start moving
they can make objects move slower
they can make objects move faster
they can make objects stop moving
they can make object change direction
Answer:
11.52 hp
Explanation:
<u><em>Givens: </em></u>
p_1 = 15 pisa
p_2 = 70 pisa
V_ol=1.5 ft^3/s
<u><em>Solution: </em></u>
Note: m = p x V_ol (assuming in compressible flow —> p =const)
The total change in the system mechanical energy can be calculated as follows,
Δ
e= (p_2 - p_1 ) /p
The power needed can be calculated as follows
P = W =mΔ
e = p x V_ol x(p_2 - p_1 ) /p
= V_ol x (p_2 - p_1 )
= 44 pisa. ft^3/s
= 44 x (1 btu/5.404pisa. ft^3) x (1 hp/0.7068btu/s)
= 11.52 hp