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3 years ago

I just need x isolated

Physics

2 answers:

mamaluj [8]3 years ago

7 0

Answer:

$x=\frac{-y+\sqrt{y^2+4rt} }{2r}$

$x=\frac{-y-\sqrt{y^2+4rt} }{2r}$

Explanation:

$rx+y=\frac{t}{x}\\\\x(rx+y)=(\frac{t}{x})x\\\\rx^2+yx=t\\\\rx^2+yx-t=t-t\\\\rx^2+yx-t=0$

Solve using the quadratic formula.

$x=\frac{-y+\sqrt{y^2+4rt} }{2r}$

$x=\frac{-y-\sqrt{y^2+4rt} }{2r}$

zepelin [54]3 years ago

4 0

Answer:

x=-y+ $\sqrt{$ y^2+4rt/2r

Explanation:

solve using the quadratic equation

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Read 2 more answers

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Explanation:

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Let $\omega_2$ is the angular velocity when the person reaches the edge. We need to find it. It can be calculated using the conservation of angular momentum as :

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