Answer:
2.3 x 10-23 g.
Explanation:
The mass of a single atom is the mass number, 14, is the mass in grams of one mole of carbon.
One mole of Nitrogen atom is 6.022 x 1023 atoms (Avogadro's number). This can then used to convert a nitogen atom to grams by the ratio:
mass of 1 atom / 1 atom = mass of a mole of atoms / 6.022 x 10^23 atoms.
mass of 1 atom = mass of a mole of atoms / 6.022 x 1023
mass of 1 N atom = 14 / 6.022 x 10^23 N atoms
mass of 1 N atom = 2.325 x 10^-23 g
The mass of a single Nitrogen atom is 2.325 x 10-23 g.
Answer:
The correct answer is
e. NH3(aq) + H+(aq) --> NH4+(aq)
Explanation:
To solve this, we write out the indidual ionization reation for aqueous ammonia and nitric acid thus
For aqueous ammonia we have
NH₃(aq) + H₂O(l) ↔ NH₄⁺(aq) + OH⁻(aq)
Aqueous ammonia is a weak base and therefore undergoes partial ionization hence the reversible reaction sign
As the level of ionization will not be more than 5% OH⁻ cannot represebt the weak base
For nitric acid we have
HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)
a strong acid like nitric acid undergoes conplete ionization in the solution
The total equation is NH₃(aq) + HNO₃(aq) → NH₄NO₃(aq)
The sum of the ionic equation is
NH₃(aq) + H⁺(aq) + NO₃⁻(aq) → NH₄⁺(aq) + NO₃⁻(aq)
The ionic equation is
NH₃(aq) + H⁺(aq) → NH₄⁺(aq)
Photosynthesis takes place in all ecosystems. Without it we would not be able to survive. Photosynthesis starts with plants. Plants are autotrophs which means they make their own food. During photosynthesis, plants take in sunlight, carbon dioxide (CO^2), and water during photosynthesis. They give off glucose and oxygen. Plants have chlorophyll in them which gives them their green color. Heterotrophs eat other living things to get energy. (If you want to go more into depth you can say this: Heterotrophs take in the glucose and oxygen. This is called cellular respiration. The products of cellular respiration are water, ATP (energy), and CO^2 which than leads you back to photosynthesis) Hope this helped! :)
When dT = Kf * molality * i
= Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
= 2.5g /250g x 1 mol /85 g x1000g/kg
=0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
= (0.1176 * 0.359)^2 / (1-0.359)
= 2.8x10^-3
The sample of smoke described above can be described as a heterogeneous mixture. This type of mixture do not have uniform properties and composition. So, getting a certain small sample would not represent the whole mixture since it does not have uniform composition.
