In the nucleus with the protons together their sum is the

Calculate how many grams would be required to prepare 600. 0 ml of 0. 150 m of naf? molar mass of naf is 41. 9 g/mo

marta [7]

Considering the definition of molarity and molar mass, the mass of NaF required is 3.771 grams.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liters}$ .

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3 /><h3>Mass of NaF required</h3>

In this case, you know:

molarity= 0.15 M= 0.15 $\frac{moles}{L}$
number of moles= ?
volume= 600 mL= 0.6 L

Replacing in the definition of molarity:

$0.15\frac{moles}{L} =\frac{number of moles}{0.6 L}$

Solving:

0.15 $\frac{moles}{L}$ × 0.6 L= number of moles

<u><em>0.09 moles= number of moles</em></u>

The molar mass of NaF is 41. 9 g/mol. So, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 41.9 grams, 0.09 moles of the compound contains how much mass?

$mass=\frac{0.09 molesx41.9 grams}{1 mole}$

<u><em>mass= 3.771 grams</em></u>

Finally, the mass of NaF required is 3.771 grams.

Learn more about

molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

molarity:

brainly.com/question/9324116

brainly.com/question/10608366

brainly.com/question/7429224

#SPJ12

4 0

2 years ago

Question 2 of 50

wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

Write the balanced chemical equation for the given reaction.
Convert the mass of calcium carbonate into moles.
Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

$CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}$

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

$mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}$

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

$mol \ CaO \ = 0.2498 \ mol$

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

$mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g$

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

$\boxed {mass \ CaO \ = 14 \ g}$

Learn More

Learn more about stoichiometry brainly.com/question/12979299
Learn more about mole conversion brainly.com/question/12972204
Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

5 0

3 years ago

Atoms join with other atoms by bonding with them in order to become as chemically ____ as possible.

zloy xaker [14]

The answer is B.) stable ... all any atom wants to do is bond with a nother to share or take electrons to have a full valence shell

5 0

3 years ago

Read 2 more answers

Use the link Standard Reduction Potentials. Write net equations for the spontaneous redox reactions that occur during the follow

GalinKa [24]

Answer:

a) Fe(s) + Ni^2+(aq) ----> Fe^2+(aq) + Ni(s)

b) no reaction

c) no reaction

d) 2Mg(s) + 2H2O(l)-----> 2Mg^2+(aq) + O2(g) +4H^+(aq)

e) no reaction

Explanation:

It is important to say here that the ability of a particular chemical specie to displace another chemical specie is dependent on the relative standard reduction potentials of the species involved.

All the reactions stated above are redox reactions. Let us take reaction E as an example. Mg^2+ has a reduction potential of -2.37 V while Cr^3+ has a reduction potential of -0.74V. Since the reduction potential of magnesium is more negative than that of chromium, there is no reaction when a piece of chromium metal is dipped into a solution of Mg^2+.

Similarly, though metals displace hydrogen gas from dilute acids, metals that are less than hydrogen in the reactivity series cannot do that. This explains why there is no reaction when copper and silver are dipped into dilute acid solutions.

Reaction occurs when iron is dipped into a nickel solution because the reduction potential of Fe^2+ is far more negative than that of Ni^2+.

7 0

4 years ago

Calcium chloride, CaCl2, is commonly used as an electrolyte in sports drinks and other beverages, including bottled water. A sol

zhannawk [14.2K]

Answer:

Mole percent of $CaCl_{2}$ in solution is 1.71%

Explanation:

Number of moles of a compound is the ratio of mass to molar mass of the compound.

Molar mass of $CaCl_{2}$ = 110.98 g/mol

Molar mass of $H_{2}O$ = 18.02 g/mol

Density is the ratio of mass to volume

So, mass of 60.0 mL of water = $(60\times 0.997)g=60.8g$

Hence, 6.50 g of $CaCl_{2}$ = $\frac{6.50}{110.98}moles$ of $CaCl_{2}$ = 0.0586 moles of $CaCl_{2}$

60.8 g of $H_{2}O$ = $\frac{60.8}{18.02}moles$ of $H_{2}O$ = 3.37 moles of $H_{2}O$

So, mole percent of $CaCl_{2}$ in solution = \frac{n_{CaCl_{2}}}{n_{total}}\times 100% = $\frac{0.0586}{0.0586+3.37}\times 100$ % = 1.71%

5 0

4 years ago