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wariber [46]
3 years ago
12

In the nucleus with the protons together their sum is the

Chemistry
2 answers:
galina1969 [7]3 years ago
6 0

Answer:

the nucleus is called the mass number and, expressed in amu, is approximately equal to the mass of the atom

Explanation:

netineya [11]3 years ago
3 0

Answer:

AMU or Atomic Mass Unit

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A 1.000 mL sample of acetone, a common solvent sometimes used as a paint remover, was placed in a small bottle whose mass was kn
ra1l [238]

Answer:

See explanation

Explanation:

Precision means the reputability of measurement and accuracy means how close a measurement is to the actual value. To get the measured mass of the acetone we need to substract the mass of the bottle from the measured mass of bottle and acetone.

The mass of the bottle is 38.0015g

⇒The mass of acetone in bottle 1= 0.7783g

⇒Mass of acetone in bottle 2= 0.7780g

⇒Mass of acetone in bottle3= 0.7786g

The measured value is near to each other. ⇒ the measurements are <u>precise</u>.

To check the <u>accuracy</u> we can compare the average value to the actual mass of the acetone.

Average of the acetone measurement is (0.7783+0.7780+0.7786)/3 = 0.7783g

The percentage of difference of the average measurement to the actual mass is = {(actual value-measured value)/actual value}x100%

={(0.7791-0.7783)/0.7791}x100%

=0.10%

So we can see the difference is very small ⇒ the measurement is accurate.

7 0
3 years ago
A geochemist in the field takes a 25.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X .
san4es73 [151]

Answer:

1- Yes, we can calculate the solubility of mineral compound X.

2- 0.012 g/mL.

Explanation:

<em>1- Using only the information above, can you calculate the solubility of X in water at 15.0 °C? </em>

The information available is:

The volume of water sample = 25.0 mL.

Weight of the mineral compound X after evaporation, drying, and washing = 0.30 g.

∴ Yes, we can calculate the solubility of mineral compound X.

<u><em>2-  If you said yes, calculate it.</em></u>

∵ 25.0 mL of water sample contains → 0.30 g of the mineral compound X.

∴ 1.0 mL  of water sample contains → ??? g of the mineral compound X.

1.0 ml of water sample will contain (0.3 g/25.0 mL) 0.012 g.

<em>∴ The solubility of the mineral compound X in the water sample is</em> <u><em>0.012 g/mL.</em></u>

<u><em></em></u>

4 0
3 years ago
aluminum has a specific heat of 0.897 j/g°C. how much heat is needed to raise the temperature of a 79 gram piece of aluminum 28°
frutty [35]

Answer:

Approximately 2000 J.

General Formulas and Concepts:

<u>Thermodynamics</u>

Specific Heat Formula: q = mcΔT

  • <em>q</em> is heat (in J)
  • <em>m</em> is mass (in g)
  • <em>c</em> is specific heat (in J/g °C)
  • ΔT is change in temperature (in °C or K)

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>c</em> = 0.897 J/g °C

[Given] <em>m</em> = 79 g

[Given] ΔT = 28°C

[Solve] <em>q</em>

<em />

<u>Step 2: Solve for </u><em><u>q</u></em>

  1. Substitute in variables [Specific Heat Formula]:                                             q = (79 g)(0.897 J/g °C)(28 °C)
  2. Multiply [Cancel out units]:                                                                               q = (70.863 J/°C)(28 °C)
  3. Multiply [Cancel out units]:                                                                               q = 1984.16 J

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

1984.16 J ≈ 2000 J

6 0
2 years ago
Which of the following is a characteristic of<br> a salt?
alexdok [17]

Answer:

Salts can be several different colors and may be any of the five tastes, including salty, sweet, bitter, sour or savory. Their odor depends on the acid and base it is comprised of. Salts comprised of strong acids and bases, called strong salts, are odorless.

8 0
3 years ago
Read 2 more answers
Calculate the gravitational force of attraction between a 26kg boy and his 5.1kg dog when they are separated by 0.19m
Pavel [41]

Answer:

Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)

Explanation:

Given:

Mass M1 = 26 kg

Mass M2 = 5.1 kg

Distance r = 0.19 m

Find:

Gravitational force of attraction G(f)

Computation:

Gravitational force of attraction G(f) = G(m1)(m2)/r²

Gravitational force of attraction G(f) = [6.67 x 10⁻¹¹](26)(5.1)/(0.19)²

Gravitational force of attraction G(f) = 8.84 x 10⁻⁹ / 0.0361

Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)

6 0
3 years ago
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