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larisa86 [58]
3 years ago
9

Describe what happens to the particles of a liquid, in terms of movement and kinetic energy, as it is cooled to its freezing poi

nt, including whether this is a physical or chemical change.
Physics
1 answer:
nataly862011 [7]3 years ago
6 0
As a system is cooled to its freezing point, the kinetic energy of the particles in the system will lower so the movement are much slower. Cooling means taking out heat from the system. This process is a physical change because it is only the phase of the system is changed and it is still the substance after the process.
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A 6kg sled sliding on an icy surface experiences a 6-N frictional force exerted by the ice and the air resistive force of 0.6 N.
White raven [17]

The net force on the sled is 6.6 N pointing backwards, opposite to the direction it's sliding. That's why it's slowing down, and will eventually stop.

5 0
3 years ago
A luge run is straight for the first 10 m. If the velocity of the luger when he passes the start line is +25 m/s and his acceler
dangina [55]
V^2 =U^2 +2AS
V^2 = 25 ^2 + 2x9.5x10
V^2 = 625 + 1900 = 2525
V = 50.25
3 0
3 years ago
Can someone explain this
Alborosie

Answer:

gravity

Explanation:

That would make the most sense from what I know

8 0
3 years ago
Read 2 more answers
A pickup truck, initially stationary at a stop light, accelerates at a rate of 1.60m/s2 for 14.0 s. The truck then cruises at co
Alex Ar [27]

Answer:

The total distance traveled by the truck is 1797 m

Explanation:

Hi there!

The equation of position and velocity of an object moving in a straight line with constant acceleration are the following:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position of the truck at time t.

x0 = initial position.

v0 = initial velocity.

a = acceleration.

t = time

v = velocity at time t.

Let's calculate the position of the truck after the first 14.0 s:

x = x0 + v0 · t + 1/2 · a · t²

If we place the origin of the frame of reference at the first stop light, the initial position, x0, is zero. Since the truck starts from rest, v0 = 0. So, the equation of position will be:

x = 1/2 · a · t²

x = 1/2 · 1.60 m/s² · (14.0 s)²

x = 157 m

Then, the truck travels with constant speed (a = 0) for 70.0 s. The equation of position will be:

x = x0 + v · t

In this case, let's consider the initial position as the the position where the car is after 14.0 s (157 m from the stop light). The velocity is the velocity reached after the 14.0 s of acceleration. Let's calculate it with the equation of velocity:

v = v0 + a · t  (v0 = 0)

v = 1.60 m/s² · 14.0 s

v = 22.4 m/s

So, the position will be:

x = 157 m + 22.4 m/s · 70.0 s

x = 1725 m

Now, the truck slows down with an acceleration of 3.50 m/s² until it stops (until its velocity is zero). Let's calculate the time at which the velocity of the truck is zero:

v = v0 + a · t

0 = 22.4 m/s - 3.50 m/s² · t

-22.4 m/s / -3.50 m/s² = t

t = 6.4 s

Now let's calculate the position of the truck after that time considering the initial position as the position at which the truck was after the 70.0 s traveling at constant speed (1725 m from the stop light):

x = x0 + v0 · t + 1/2 · a · t²

x = 1725 m + 22.4 m/s · 6.4 s + 1/2 · (-3.50 m/s²) · (6.4 s)²

x = 1797 m

The total distance traveled by the truck is 1797 m

7 0
3 years ago
50 POINTS AND BRAINLIST!!!PLEASE HELP FOR BRAINLIST! Give answer and explanation/ work
UkoKoshka [18]

20 joule is your answer

Answer:

here

mass m =100kg

distance d=50m

acceleration due to gravity a =10m/s²

work =force×displacement

= ma/d=100×10/50=20joule

4 0
2 years ago
Read 2 more answers
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