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Evgesh-ka [11]
3 years ago
5

At about 55 meters/sec, a falling parachuter (before the parachute opens) no longer accelerates. Air friction opposes accelerati

on. Although the affect of air friction begins gradually, imagine that the parachuter is free falling until terminal speed ( the constant falling speed) is reached. How long would that take?
Physics
1 answer:
JulijaS [17]3 years ago
3 0
The acceleration of gravity on Earth is about 9.8 m/s².
That means that if air resistance is neglected, a falling body
smoothly gains 9.8 m/s of downward speed each second.

If our intrepid chutist lightly stepped out of the plane or was
gently pushed, so that his initial downward speed was zero
and grew by 9.8 m/s every second, then it took him ...

               (55) / (9.8)  =  5.6 seconds

to reach that particular downward speed.
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We observe a glowing cloud of gas in space with a spectroscope. We note that many of the familiar lines of hydrogen that we know
konstantin123 [22]

Answer:

No information can be concluded from this observation alone the cloud is much cooler than hydrogen on Earth

4 0
3 years ago
g A mass of 2.0 kg traveling at 3.0 m/s along a smooth, horizontal plane hits a relaxed spring. The mass is slowed to zero veloc
dezoksy [38]

By the work-energy theorem, the total work done on the mass by the spring is equal to the change in the mass's kinetic energy:

<em>W</em> = ∆<em>K</em>

and the work done by a spring with constant <em>k</em> as it gets compressed a distance <em>x</em> is -1/2 <em>kx</em> ²; the work it does is negative because the restoring force of the spring points opposite the direction in which it's getting compressed.

So we have

-1/2 <em>k</em> (0.15 m)² = 0 - 1/2 (2.0 kg) (3.0 m/s)²

Solve for <em>k</em> to get <em>k</em> = 800 N/m.

8 0
3 years ago
A unit that is equal to 33 000 ft-lbs/min or 550 ft-lbs/s is the
statuscvo [17]
<h2>Answer to Q1: </h2>

<u>A unit that is equal to 33 000 ft-lbs/min or 550 ft-lbs/s is the</u><u>  horsepower</u>

<h2>Explanation:</h2>

Prefix or symbol for horsepower is: hp


Prefix or symbol for foot pound per minute is: ft-lb/min.  

One horsepower converted into foot pound per minute equals = 33,000.00 ft-lb/min


1 hp = 33,000.00 ft-lb/min


So horsepower is the correct answer



<h2>Answer to Q2: </h2>

The work done is 36456 J


<h2> Explanation: </h2>

Length of corridor = 14.33 m


Length of 3 corridors = 14.33 x 3 = 42.99


And,


Force = 848


As we know Work = Force x Displacement


Work = 848 x 42.99 = 36456 J



<h2>Answer to Q3: </h2>

The velocity will be 0.14 m/s


<h2>Explanation: </h2>

Since the length is given as 42.00 in the previous questions so we will use the same length


Now the time given is 5 minutes which is equal to 300 seconds


As we know velocity = distance / time


Velocity = 42.99 / 300


Velocity = 0.14 m/s



<h2>Answer to Q4: </h2>

Centripetal acceleration = 0.54 m/s^2


<h2>Explanation: </h2>

The centripetal acceleration is given by V^2 / r


So centripetal acceleration = 0.57 / 0.6


Centripetal acceleration = 0.54 m/s^2


Therefore 0.54 is the correct answer

Answer to Q5

The answer is 46.67 m/min

Explanation:

From the question statement we observe that

r=3.79 m  and  t=.51 min

We have to find distance covered by a cog which is equal to the circumference of gears rotation.

d=2πr

d=2π(3.79)

d=23.8 m

so putting the values of d and t in the velocity formula we get

v=23.8/.51

v=46.67 m/min which is the answer.


Answer to Q 6

The answer is 23.8 m

Explanation:

From the question statement, we observe that

r=3.79 m

The distance is equal to the circumference of gears rotation.

So, the formula for distance is d=2πr

d=2π(3.79)

d=23.8 m which is the correct answer


<h2>Answer to Q 7 </h2>

Power = 245 Watts


<h2>Explanation: </h2>

The power formula is  

P = Work / time


Here work = potential energy


Potential Energy = mgh


So  

Power = mgh / time


Power = 50 x 9.8 x 1 and divided by 2


Power = 490 / 2


Power = 245 Watts




3 0
3 years ago
Read 2 more answers
James took two pea plants, placing one in a dark closet and the other on a sunny window sill. Both are located in air-conditione
Fudgin [204]

The constant is the temperature of the air that the plants get.

The independent variable is the thing that YOU control.  That's the amount of sunlight each plant gets.

The <em>dependent variable</em> is anything that's caused by changes in the independent variable.  That's the growth of the plants.

5 0
4 years ago
Read 2 more answers
A javelin thrower standing at rest holds the center of the javelin behind her head, then accelerates it through a distance of 70
JulijaS [17]

Answer:

a = 580 m/s^2

Explanation:

Given:

- Distance for accelerated throw s_a = 70 cm

- Angle of throw Q = 30 degrees

- Distance traveled by the javelin in horizontal direction x(f) = 75 m

- Initial height of throw y(0) = 0

- Final height of the javelin y(f) = -2 m

Find:

What was the acceleration of the javelin during the throw? Assume that it has a constant acceleration.

Solution:

- Compute initial components of the velocity:

                                             V_x,i = V*cos(30)

                                             V_y,i = V*sin(30)

- Use second equation of motion in horizontal direction:

                                          x(f) = x(0) + V*cos(30)*t

                                            75 = 0 + V*cos(30)*t

                                              t = 75 /V*cos(30)

- Use equation of motion in vertical direction:

                                     y(f) = y(0) + V_y,i*t + 0.5*g*t^2

Subs the values:

                      -2 = 0 + V*sin(30)*75/V*cos(30) - 4.905*(75/Vcos(30))^2

                           -2 = 75*tan(30) - 4.905*(5625/V^2*cos^2(30))

                           V^2 = 4.905*5625 / (2 + 75*tan(30))*cos^2(30)

                                                V^2 = 812.0633

                                                 V = 28.5 m/s

- Use the third equation of motion in the interval of the throw:

                                            V^2 = U^2 + 2*a*s_a

                                               28.5^2 = 2*a*0.7

                                                a = 580 m/s^2

         

     

6 0
3 years ago
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