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Akimi4 [234]
3 years ago
9

A 17 H inductor carries a current of 1.8 A. At what rate must the current be changed to produce a 70 V emf in the inductor?

Physics
1 answer:
pogonyaev3 years ago
5 0

Answer:

at rate the current change is 6.75 A / sec

Explanation:

given data

inductance L  = 17 H

current I = 1.8 A

emf  e = 70 V

to find out

At what rate must the current be changed

solution

we will apply here emf formula that is

emf =  inductance (di/dt)

so  here (di/dt)  will be

di/dt = emf  /  inductance    .......................1

put  value of emf and inductance in equation 1 we get rate

di/dt = 81 / 12

di/dt = 6.75 A / sec

so at rate the current change is 6.75 A / sec

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uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is th
adoni [48]

Answer:

potential difference V= 300 volts

Explanation:

Given:

d= 2.0 cm = 0.02m

E = 15 kN/C = 15 × 10³ N/C

For a uniform field between two plates, the Electric Filed Intensity (E) is proportional to the potential difference (V) and inversely  proportional to distance between the plates.

E= V/d

⇒ V= E×d = 15 × 10³ N/C × 0.02 m = 300 volts  (∴1 Nm/C = 1 J/C= 1 volts)

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Margaret wants to go for a swim, and decides to jump in using the diving board that measures 3-m long.
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Marizza181 [45]

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Explanation:

6 0
2 years ago
PLEASEEE HELPPPPPPP:
tatuchka [14]
V(voltage) = I(current)R(resistance)
substitute in the values

V = 15 * 0.10
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