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damaskus [11]
3 years ago
11

A 150 kg object and a 450 kg object are separated by 0.430 m. (a) find the net gravitational force exerted by these objects on a

39.0 kg object placed midway between them.
Physics
1 answer:
Dvinal [7]3 years ago
4 0
Forces are vectors. They cancel each other when in opposite directions. Use the equation F=GMm/r^2 and find the difference between the two forces since they are directly opposing each other.
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Explain how fluids exert pressure
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4 0
2 years ago
A 0.600 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with
gulaghasi [49]

Answer:

8.8 cm

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Explanation:

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x = Compression of spring

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As the energy of the system is conserved we have

\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{0.6\times 0.44^2}{15}}\\\Rightarrow A=0.088\ m\\\Rightarrow A=8.8\ cm

Amplitude of the oscillations is 8.8 cm

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Again, as the energy of the system is conserved we have

\dfrac{1}{2}kA^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2\\\Rightarrow v=\sqrt{\dfrac{k(A^2-x^2)}{m}}\\\Rightarrow v=\sqrt{\dfrac{15(0.088^2-(0.7\times 0.088)^2)}{0.6}}\\\Rightarrow v=0.31422\ m/s

The block's speed is 31.422 cm/s

4 0
3 years ago
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