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Anna11 [10]
3 years ago
10

Calculate the approximate volume of a uranium nucleus, 23592u. (you can ignore the mass defect in this calculation and simply ta

ke the mass of the nucleus to be equal to the sum of the masses of its nucleons.)
Physics
1 answer:
tester [92]3 years ago
5 0

Radius of nuclei is given by formula

R = R_oA^{1/3}

now we can say volume of the nuclei is given as

V = \frac{4}{3}\pi R_o^3* A

now the density is given as

density = mass / volume

mass of nuclei = mass of neutron + mass of protons

m = z*m_p + (A- z)*m_n

m_p = m_n = 1.008u

m = A*1.008u

Now density is given as

\rho = \frac{A*1.008u}{\frac{4}{3}\pi R_0^3* A}

here we know that

R_0 = 1.2 fm

\rho = \frac{1.008u}{\frac{4}{3}\pi*(1.2*10^{-15})^3}

\rho = 2.31 * 10^{17} kg/m^3

So from above we can say that density of all nuclei is almost same.

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The increase in volume of matter that occurs when matter is heated. a) Contraction b) Expansion c) kinetic energy d) Volume
katrin2010 [14]

Answer:

b) Expansion

Explanation:

In science, matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.

Generally, matter exists in three (3) distinct or classical phases and these are; solid, liquid and gas.

A physical change can be defined as a type of change that involves an increase or decrease in the volume of a physical object (object). Also, this change can be reversed to the original state under certain conditions.

The increase in volume of matter that occurs when matter is heated causes an expansion.

This ultimately implies that, when a physical object (matter) is heated for a specific period of time, it result in an increase in the volume of the object; this phenomenon is generally referred to as expansion.

On the other hand, a decrease in volume of a physical object (matter) as a result of heat is known as contraction.

7 0
2 years ago
A green light is submerged 2.70 m beneath the surface of a liquid with an index of refraction 1.31. What is the radius of the ci
Anettt [7]

Answer:

The radius is  r = 3.1905 \ m

Explanation:

From the question we are told that

        The  distance  beneath the liquid  is  d =  2.70 \ m

        The refractive index of the liquid is  n_i  =  1.31

Now the critical value is mathematically represented as

         \theta =  sin ^{-1} [\frac{1}{n_i} ]

substituting values

         \theta =  sin ^{-1} [\frac{1}{131} ]

         \theta  =  49.76^o

Using SOHCAHTOA rule we have that

         tan \theta =  \frac{ r}{d}

=>     r =  d * tan \theta

substituting values  

        r =  2.7 * tan (49.76)

        r = 3.1905 \ m

         

5 0
3 years ago
The description for a certain brand of house paint claims a coverage of 475 ft²/gal.
AlexFokin [52]

Answer:

(a) 11.66 square meters per liter

(b) 11657.8 per meters

(c) 0.00211 gal per square feet

Explanation:

(a) 475ft^2/gal = 475ft^2/gal × (1m/3.2808ft)^2 × 1gal/3.7854L = 11.66m^2/L

(b) 475ft^2/gal = 475ft^2/gal × (1m/3.2808ft)^2 × 264.17gal/1m^3 = 11657.8/m

(c) Inverse of 475ft^2/gal = 1/475ft^3/gal = 0.00211gal/ft^3

8 0
3 years ago
A student tosses a ball horizontally from a balcony to a friend 3.8 meters down below them. How long does the ball take to reach
Vsevolod [243]

Answer:

The time it takes the ball to fall 3.8 meters to friend below is approximately 0.88 seconds

Explanation:

The height from which the student tosses the ball to a friend, h = 3.8 meters above the friend

The direction in which the student tosses the ball = The horizontal direction

Given that the ball is tossed in the horizontal direction, and not the vertical direction, the initial vertical component of the velocity of the ball = 0

The equation of the vertical motion of the ball can therefore, be represented by the free fall equation as follows;

h = 1/2 × g × t²

Where;

g = The acceleration due gravity of the ball = 9.81 m/s²

t = The time of motion to cover height, h

Then height is already given as h = 3.8 m

Substituting gives;

3.8 = 1/2 × 9.81 × t²

t² = 3.8/(1/2 × 9.81) ≈ 0.775 s²

∴ t = √0.775 ≈ 0.88 seconds

The time it takes the ball to fall 3.8 meters to friend below is t ≈ 0.88 seconds.

8 0
3 years ago
sledge (including load) weighs 5000 N. It is pulled on level snow by a dog team exerting ahorizontal force on it. The coefficient
lara31 [8.8K]

Answer:

2.5 x 10^{5} J

Explanation:

weight = 5,000 N

coefficient of friction = 0.05

distance = 1000 m

how much work is done by the dogs pulling the sledge

work done = force x coefficient of friction x distance

work done = 5000 x 0.05 x 1000 = 2.5 x 10^{5} J

6 0
3 years ago
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