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Anna11 [10]
3 years ago
10

Calculate the approximate volume of a uranium nucleus, 23592u. (you can ignore the mass defect in this calculation and simply ta

ke the mass of the nucleus to be equal to the sum of the masses of its nucleons.)
Physics
1 answer:
tester [92]3 years ago
5 0

Radius of nuclei is given by formula

R = R_oA^{1/3}

now we can say volume of the nuclei is given as

V = \frac{4}{3}\pi R_o^3* A

now the density is given as

density = mass / volume

mass of nuclei = mass of neutron + mass of protons

m = z*m_p + (A- z)*m_n

m_p = m_n = 1.008u

m = A*1.008u

Now density is given as

\rho = \frac{A*1.008u}{\frac{4}{3}\pi R_0^3* A}

here we know that

R_0 = 1.2 fm

\rho = \frac{1.008u}{\frac{4}{3}\pi*(1.2*10^{-15})^3}

\rho = 2.31 * 10^{17} kg/m^3

So from above we can say that density of all nuclei is almost same.

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An object is moving in a straight line along the y axis. As a function of time, its position is given by the equation y=3.0+4.8x
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Answer:

Explanation:

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Note we have changed the last term to be quadratic, so the question has more sense.

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3 years ago
A proton initially at rest is accelerated by a uniform electric field. The proton moves 5.62 cm in 1.15 x 10^-6 s. Find the volt
krok68 [10]

Answer:

49.85 V

Explanation:

u = 0, s = 5.62 cm, t = 1.15 x 10^-6 s

Let the electric field is E and voltage is V.

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5.62 x 10^-2 = 0 + 0.5 a x (1.15 x 10^-6)^2

a = 8.5 x 10^10 m/s^2

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E = m x a / q

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