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lbvjy [14]
3 years ago
15

Model rocket engines are rated by the impulse that they deliver when they fire. A particular engine is rated to deliver an impul

se of 3.5 kg #m/s. The engine powers a 120 g rocket, including the mass of the engine. What is the final speed of the rocket once the engine has fired?
Physics
1 answer:
abruzzese [7]3 years ago
4 0

Answer:

Final speed of the rocket, \Delta v= 29.16\ m/s

Explanation:

It is given that,

Impulse delivered by an engine, J = 3.5 kg-m/s

Mass of the rocket, m = 120 g = 0.12 kg

To find,

The final speed of the rocket

Solution,

We know that the impulse is equal to the product of mass and velocity o it is equivalent to the change in momentum of an object.

J=\Delta P=m\times \Delta v

\Delta v=\dfrac{J}{m}

\Delta v=\dfrac{3.5\ kg-m/s}{0.12\ kg}

\Delta v= 29.16\ m/s

So, the final speed of the rocket once the engine has fired is 29.16 m/s.

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A bus accelerates to 60 m/s to the east in 10 s. What is the buses acceleration? 2. A car traveling at 10.0 m/s to the west acce
professor190 [17]

Answers:

1) a=6\frac{m}{s^{2}}

2) t=8s

Explanation:

1) Acceleration a is defined as the variation of Velocity V in time t :  

a=\frac{V}{t}  (1)

A body also has acceleration when it changes its direction.

In this case we have a bus with a velocity of 60m/s to the east, that accelerates in a time 10s. So, we have to find the bus's acceleration:

a=\frac{60m/s}{10s}  (2)

a=6m/s^{2}  (3)  This is the bus's accelerration

2) Now we have a car that accelerates 2m/s^{2}  to the west in order to reach a speed of 16m/s in the same direction, and we have to find the time t it takes to the car to reach that velocity.

Therefore we have to find  t from (1):

t=\frac{V}{a}  (4)

t=\frac{16m/s}{2m/s^{2}}  (5)

Finally:

t=8s  (6)

3 0
3 years ago
What is the SI unit of electric charge
shusha [124]

Answer:

The SI unit for electric chargeis the C (which is the abbreviation of Coulomb}

Explanation:

The SI unit for electric chargeis the Coulomb. The letter used is the C.

1 C = 1 As

4 0
3 years ago
The transverse standing wave on a string fixed at both ends is vibrating at its fundamental frequency of 250 Hz. What would be t
hodyreva [135]

Answer:

Explanation:

fundamental frequency, f = 250 Hz

Let T be the tension in the string and length of the string is l ans m be the mass of the string initially.

the formula for the frequency is given by

f=\frac{1}{2l}\sqrt{\frac{Tl}{m}}    .... (1)

Now the length is doubled ans the tension is four times but the mass remains same.

let the frequency is f'

f'=\frac{1}{2\times 2l}\sqrt{\frac{4T\times 2l}{m}}    .... (2)

Divide equation (2) by equation (1)

f' = √2 x f

f' = 1.414 x 250

f' = 353.5 Hz

7 0
3 years ago
Which characteristic of a sound is affected by the amount of energy used to create that sound? In what direction the sound will
olya-2409 [2.1K]

Answer:

The correct option is;

How loud or soft the sound is

Explanation:

The loudness of a sound wave is given by the amount of energy that the pressure wave carries and it is measured in decibels (dB) which is the relative intensity of the pressure wave of a sound to the standard pressure

A loud sound has a high amplitude and a soft sound has a low amplitude, such that as the amplitude of the sound is increased, due to increased energy input, the sound becomes louder, and as the amplitude of the sound is decreased due to reduced energy input, the sound becomes softer.

5 0
2 years ago
What is coulomb law​
MrRa [10]

Answer:Coulomb's law states that: The magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.

Explanation:Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force

6 0
3 years ago
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