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3 years ago

Which of these structures is an architect most likely to design?

Physics

2 answers:

tankabanditka [31]3 years ago

4 0

Answer:

Explanation:

C...

cupoosta [38]3 years ago

3 0

Sculpture is the correct answer

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6) Calculate the area of a body which experiences a pressure of 60000 Pa by a force of 120N

Vika [28.1K]

Answer:

area = force by pressure

or, a = 120N by 60000 Pa

or, a= 0.002 m²

4 0

4 years ago

Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms

lakkis [162]

Answer:

(a) 333.77 J

(b) 237.85 J

(d) 4667.85 J

Explanation:

Temperature of source, TH = 314 K

Temperature of A, Tc = 292 K

Temperature of B, Tc' = 298 K

heat taken out, Qc = 4430 J

Let the heat deposited outside is QH and QH' by A and B respectively.

$\frac{Q_H}{Q_c}=\frac{T_H}{T_c}\\\\Q_H = \frac{4430\times314}{292}=4763.77 J$

Now

$\frac{Q_H'}{Q_c}=\frac{T_H}{T_c'}\\\\Q_H' = \frac{4430\times314}{298}=4667.85 J$

(a) Work done for A

W = QH - QC = 4763.77 - 4430 = 333.77 J

(b) Work done for B

W' = QH' - Qc = 4667.85 - 4430 = 237.85 J

(d) QH' = 4667.85 J

4 0

3 years ago

Which statement about convection in the Earth's mantle is true?

marissa [1.9K]

Answer:

All of these

Explanation:

Mantle convection causes tectonic plates to move around and passes heat on the earth surface in forms of lava and magma.

Hope it helps!

4 0

3 years ago

Refrigerators are usually kept at about 5∘C, while room temperature is about 20∘C. If you were to take an "empty" sealed 2-liter

expeople1 [14]

Answer:

The volume will not contract to one fourth of the original.

Explanation:

Applying Charles's Law as:

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = ?

V₂ = 2 L

T₁ = 5 °C

T₂ = 20 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (5 + 273.15) K = 278.15 K

T₂ = (20 + 273.15) K = 293.15 K

Using Charles law as:

$V_1=\frac {V_2}{T_2} \times {T_1}$

$V_1=\frac {2\ L}{293.15 K} \times {278.15 K}$

$V_1=1.8977 L$

Thus, the volume will not contract to one fourth of the original. (1/4 of 2 L is 0.5 L).

8 0

4 years ago

A cube of ice at an initial temperature of -15.00°C weighing 12.5 g total is placed in 85.0 g of water at an initial temperature

Leona [35]

Answer: The specific heat of ice is 2.11 J/g°C

Explanation:

When ice is mixed with water, the amount of heat released by water will be equal to the amount of heat absorbed by ice.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of ice = 12.5 g

$m_2$ = mass of water = 85.0 g

$T_{final}$ = final temperature = 22.24°C

$T_1$ = initial temperature of ice = -15.00°C

$T_2$ = initial temperature of water = 25.00°C

$c_1$ = specific heat of ice = ?

$c_2$ = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

$12.5\times c_1\times (22.24-(-15))=-[85.0\times 4.186\times (22.24-25)]$

$c_1=2.11J/g^oC$

Hence, the specific heat of ice is 2.11 J/g°C

3 0

4 years ago