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Vitek1552 [10]
3 years ago
12

Which of these structures is an architect most likely to design?

Physics
2 answers:
tankabanditka [31]3 years ago
4 0

Answer:

Explanation:

C...

cupoosta [38]3 years ago
3 0
Sculpture is the correct answer
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PLS ANSWERR THIS QUESTION FOR ME !!
MA_775_DIABLO [31]

Explanation:

20 joule is your answer

Answer:

here

mass m =100kg

distance d=50m

acceleration due to gravity a =10m/s²

work =force×displacement

= ma/d=100×10/50=20joule

3 0
3 years ago
Read 2 more answers
While mowing your lawn, you push a lawnmower 120. m with a constant force of 300. N. How much work have you done, assuming that
Montano1993 [528]
We have: Work done = Force × Displacement
Here, Force = 300 N
Displacement = 120 m

Substitute their values into the formula:
W = 300 × 120 
W = 36000

In scientific notation, it would be: 3.6 × 10⁴

Finally, option C would be your correct answer.

Hope this helps!
3 0
3 years ago
The atmospheric pressure above a swimming pool changes from 837 to 842 mm of mercury. The bottom of the pool is a rectangle (10
maxonik [38]

Answer:

Change in force = 1.66 × 10⁵ N

Explanation:

Given:

Initial pressure = 837 mmHg

Final pressure = 842 mmHg

Rectangle (10 m ⨯ 25 m)

Find:

Change in force

Computation:

Change in force = (Change in pressure)(Area)(133 pa / 1 mmHg)

Change in force = (842 - 837)(10 m ⨯ 25 m)(133 pa / 1 mmHg)

Change in force = (166,250)

Change in force = 1.66 × 10⁵ N

8 0
3 years ago
Please guys help me with this question.​ please show the working
yawa3891 [41]

Answer:

lolllll

Explanation:

looobsbsbjwkskkskwk else's sjwbs w ksj

8 0
3 years ago
A soccer player kicks a ball, changing its momentum by 11\, \dfrac {\text{kg}\cdot \text m}{\text s}11 s kg⋅m ​ 11, start fracti
dalvyx [7]

Answer:

0.012  seconds

Explanation:

The time at which the soccer player maintain contact with the ball is as follows:

Given that

Change in momentum = 11 kg.m.s^-1

The Net force applied = F = 910 N

Now the following formulas should be applied:

For acceleration:

a = \frac{\triangle v}{\triangle t} \\\\\triangle v = a \triangle t

For momentum

\triangle p = m\triangle v\\\\\triangle p = ma\triangle t\\\\\triangle p = f\triangle t\\\\\triangle t = \frac{\triangle p}{F}

Now

Put  the values to the above formula

= 11 ÷ 910

= 0.012 seconds

3 0
3 years ago
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