MgCl2 because it is the only option in which a metal appears with a nonmetal. In this case, the metal transfers electrons to the nonmental because the metal has a lower ionization energy.
Answer:
a) 32.09 kPa
b) 32.09 kPa
Explanation:
Given data:
rate constant 
initial pressure is = 32.1 kPa
half life of A is calculated as



for calculating pressure we have follwing expression


a) 
b) 
Answer:
c
Explanation:
use %composition given to calculate emperical 4mular
Answer:
malleable
Explanation:
physical properties of matter include colour, hardness, malleability, solubility, density etc
Al(NO3)3 + 3KOH -------> 3KNO3 + Al(OH)3
50 ml * .2 moles/ liter = .01 Moles of Al(NO3)3
200 ml * .1 moles/liter = .02 Moles of KOH
Since the ratio between the two reactants according to the chemical equation is 1:3, we would need .03 moles of one to fully react with .01 moles of the other. Since we don't, only 1/150 mole of the first reactant will react with the .02 moles of the second reactant. This will produce .02 moles of KNO3 as well as .01 moles of Al(OH)3
.02 moles KNO3 = .02(48 grams + 14 grams + 40 grams) = .02(102 grams) = 2.04 grams