Does the total charge change when we charge an object ?

Visible light travels at a speed 3.0 × 108 of m/s. If red light has a wavelength of 6.5 × 10–7 m, what the frequency of this lig

gayaneshka [121]

i think its d on edge

4 0

3 years ago

Read 2 more answers

Give me the ans of this plsss

MissTica

vib. motion motion of wire of guitar

circular motion revolution of earth around sun

1ml 1cm3

1m3 100cm3

volume of liquid measuring cylinder

5 0

3 years ago

A positive charge is placed at rest at the center of a region of space in which there is a uniform electric field. (A uniform fi

Harlamova29_29 [7]

Answer:

.D.It will decrease because the charge will move in the direction of the electric field

Explanation:

<em>which there is a uniform electric field. (A uniform field is one whose strength and direction are the same at all points within the region.) What happens to the electric potential energy of the positive charge, after the charge is released from rest in the uniform electric field?A. It will remain constant because the electric field is uniform.B.It will decrease because the charge will move in the opposite direction of the electric field.C.It will remain constant because the charge remains at rest.D.It will decrease because the charge will move in the direction of the electric field.E.It will increase because the charge will move in the direction of the electric field.</em>

solution

The potential energy decreases, converted to kinetic energy

The charge will feel a force in the direction of the electric field (F=Eq) and thus it will accelerate with

a constant acceleration. (Just like releasing an object above the earth's surface - constant acceleration,

at least until it hits something.)

tus te answer will be

.D.It will decrease because the charge will move in the direction of the electric field

7 0

3 years ago

Three different objects, all with different masses, are initially at rest at the bottom of a set of steps. Each step is of unifo

fgiga [73]

The definition of gravitational potential energy would gravitate allows to find the answers for the energy of each object on the highest rung of the ladder are:

a) expression for gravitational potential energy is $U_p = m g \ \Delta y$

b) Energy value

* Body 1 U_p = 82 J

* Body 2 U_p = 38.6 J

* Body 3 18.5 J

The gravitational potential energy is a configuration energy that represents the amount of work that the system can do for a given configuration, its expression is

$U_p = m g \ \Delta y$

Where $U_p$ is the gravitational potential energy, m the mass of the body and Δy the difference in height.

In this case it indicates that the minimum height is at the bottom and is equal to zero, the steps of a ladder have a height of approximately y = 15 cm = 0.15 m

They indicate the mass of the bodies are m₁ = 3.10 kg, the mass of the body 2 m₂ = 1.46 kg , the mass of the third object is not observed, suppose it is m₃ = 0.7 kg.

They indicate that the body is placed on the last step, suppose it is a standard 18-step ladder, therefore the total height is

y = # _ steps y_each step

y = 18 0.15

y = 2.70 m

the gravitational potential energy to the capacity of the body is

body 1

$U_p$ = m₁ g Δy₁

U_p = 3.10 9.8 (2.70 -0)

U_p = 82 J

body 2

U_p = 1.46 9.8 ( 2.7-0)

U_p = 38.6 J

body 3

U_pUp = 0.70 9.8 (2.7-0)

U_p = 18.5 J

In conclusion, using the definition of gravitational potential energy, we can find the answers for the energy of each object on the highest rung of the ladder are;

a) expression for gravitational potential energy is $U_p = m g \ \Delta y$

b) Energy value

* Body 1 U_p = 82.0 J

* Body 2 U_p = 38.6 J

* Body 3 U_p = 18.5 J

Learn more here: brainly.com/question/3884855

8 0

3 years ago

Write the y-equation for a wave traveling in the negative x-direction with wavelength 50 cm, speed 4.0 m/s, and amplitude 5.0 cm

Zanzabum

Answer:

$y = A sin(2\pi(\dfrac{x}{50})+ 8 t)$