Mass plus atomic and number
atomic mass=percentage of isotope a * mass of isotope a + percentage of isotope b * mass of isotope b+...+percentage of isotope n * mass of isotope n.
Data:
mass of isotope₁=267.8 u
percentage of isotope₁=90.3%
mass of isotope₂=270.9 u
percentage of isotope₂=9.7%
Therefore:
atomic mass=(0.903)(267.8 u)+(0.097)(270.9 u)=
=241.8234 u + 26.2773 u≈268.1 u
Answer: the mass atomic of this element would be 268.1 u
Answer:
2.645
Explanation:
Rate of diffusion formula:
Sqrt(mass2/mass1)
>>sqrt(14/2)
(Note:Hydrogen must exist in dwiatomic, [H2])
Answer: 20.0 g of hydrogen chloride must simultaneously be formed
Explanation:
The balanced chemical reaction is :

According to the law of conservation of mass, mass can neither be created nor be destroyed. The mass on reactant side must be equal to the mass on product side.
Thus mass of reactants = mass of products
Given : mass of ammonium chloride = mass of reactants = 29.4 g
mass of ammonia = 9.4 g
mass of products = mass of ammonia + mass of hydrogen chloride
9.4 g +mass of hydrogen chloride = 29.4 g
mass of hydrogen chloride = 20.0 g