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Yanka [14]
3 years ago
12

If the average mass of an adult is 86kg. Determine the mass and weight of an 86kg man in the moon where gravitational field is o

ne-sixth that of the earth.
Physics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

See the explanation below, and the different answers

Explanation:

It is important to clarify that the mass is always preserved, that is, it does not vary regardless of the location of the person, whether the moon, Saturn, Mars. The value that changes is the weight, due to the gravity of each planet.

<u>On Earth</u>

<u />

m = 86[kg]

w = m * g

where:

g = gravity acceleration = 9.81[m/s^2]

w = weight = [N]

w = 86 * 9.81

w = 843.66 [N]

<u>On the Moon</u>

<u />

m = 86[kg]

w = m * g

where:

g = gravity acceleration * (1/6) = 9.81 * (1/6) = 1.635 [m/s^2]

w = weight = [N]

w = 86 * 1.635

w = 140.61 [N]

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The compound magnesium phosphate has the chemical formula Mg3(PO4)2. In this compound, phosphorous and oxygen act together as on
S_A_V [24]

The question is incomplete, the complete question is;

The compound magnesium phosphate has the chemical formula Mg3(PO4)2. In this compound, phosphorus and oxygen act together as one charged particle, which is connected to magnesium, the other charged particle. What does the 2 mean in the formula 5Mg3(PO4)2? A. There are two elements in magnesium phosphate. B. There are two molecules of magnesium phosphate. C. There are two magnesium ions in a molecule of magnesium phosphate. D. There are two phosphate ions in a molecule of magnesium phosphate.

Answer:

There are two phosphate ions in a molecule of magnesium phosphate.

Explanation:

The compound magnesium phosphate is an ionic compound. Ionic compounds always consists of two ions, a positive ion and a negative ion.

In this case, the positive ion is Mg^2+ while the negative ion is PO4^3-.

The subscript, 2 after the formula of the phosphate ion means that there are two phosphate ions in each formula unit of magnesium phosphate.

5 0
2 years ago
PLEASE HELP A cup of water and a swimming pool full of water are at 24°C. The _____ of the swimming pool is higher. 1.heat conte
Dimas [21]

Answer:

4. kinetic energy

4 0
3 years ago
Question 1 of 7What is the change in internal energy if 90 J of thermal energy is added to asystem, and the system does 30 J of
Dmitriy789 [7]

Given:

The thermal energy added to the system is Q = 90 J

The work done by the system on the surroundings is W = 30 J

To find the change in internal energy.

Explanation:

According to the first law of thermodynamics, the change in internal energy can be calculated by the formula

\Delta U=\text{ Q-W}

On substituting the values, the change in internal energy will be

\begin{gathered} \Delta U\text{ =90-30} \\ =60\text{ J} \end{gathered}

Final Answer: The chage in internal energy is 60 J (option D)

5 0
11 months ago
Write the formula of Lever, Pulleys, wheel and axle and inclined plane.<br>​
maxonik [38]

Answer:

Lever => d_{e} = d_{r}

Pulley => G = M x n (gravitational acceleration)

Wheel and axle => M.A = Radius of the wheel/radius of the axle = R/r

Inclined plane => It can be divided into two components: Fi = Fg * sinθ - parallel to inclined plane. Fn = Fg * cosθ - perpendicular one.

6 0
2 years ago
An experiment is done to compare the initial speed of projectiles fired from high-performance catapults. The catapults are place
anzhelika [568]

Answer:1.084

Explanation:

Given

mass of Pendulum M=10 kg

mass of bullet m=5.5 gm

velocity of bullet u

After collision let say velocity is v

conserving momentum we get

mu=(M+m)v

v=\frac{m}{M+m}\times u

Conserving Energy for Pendulum

Kinetic Energy=Potential Energy

\frac{(M+m)v^2}{2}=(M+m)gh

here h=L(1-\cos \theta ) from diagram

therefore

v=\sqrt{2gL(1-\cos \theta )}

initial velocity in terms of v

u=\frac{M+m}{m}\times \sqrt{2gL(1-\cos \theta )}

For first case \theta =6.8^{\circ}

u_1=\frac{M+m_1}{m_1}\times \sqrt{2gL(1-\cos 6.8)}

for second case \theta =11.4^{\circ}

u_2=\frac{M+m_2}{m_2}\times \sqrt{2gL(1-\cos 11.4)}

Therefore \frac{u_1}{u_2}=\frac{\frac{M+m_1}{m_1}\times \sqrt{2gL(1-\cos 6.8)}}{\frac{M+m_2}{m_2}\times \sqrt{2gL(1-\cos 11.4)}}

\frac{u_1}{u_2}=\frac{1819.181\times 0.0838}{1001\times 0.1404}

\frac{u_1}{u_2}=1.084

i.e.\frac{v_1}{v_2}=1.084

4 0
3 years ago
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