Venus has a higher average surface temperature than mercury. why?

A state trooper is traveling down the interstate at 20 m/s. He sees a speeder traveling at 50 m/s approaching from behind. At th

Vaselesa [24]

Answer:

Explanation:

From the given information;

Let assume that the distance travelled by the speeder prior to the time the trooper catches with it to be = d

the time interval to be = t

Then, the speeder speed = distance/time

Making distance the subject; then:

distance (d) = speed × time

d = (50 m/s)t

d = 50 t --- (1)

Now, for the trooper; Using the equation of motion:

$d = ut + \dfrac{1}{2}at^2$

$d = (20)t+\dfrac{1}{2}(2.5)t^2$

d = 20t + 1.25t²

Replace the value of d in (1) to the above equation, we have:

50 t = 20 t + 1.25t²

50t - 20t = 1.25t²

30t = 1.25t²

30 = 1.25t

$t = \dfrac{30}{1.25}$

t = 24 seconds

From (1), the distance far down the highway the trooper will travel prior to the time it catches up with the speeder is:

= 50t

= 50(24)

= 1200 seconds

8 0

3 years ago

Help plz I don't understand

Vika [28.1K]

#78

Airplane start with initial speed

$v_i = 0$

now the takeoff velocity is given as

$v_f = 300 km/h$

$v_f = 83.33 m/s$

acceelration is given as

$a = 1 m/s^2$

now we have

$v_f - v_i = at$

from above equation we have

$83.33 - 0 = 1(t)$

$t = 83.33 s$

#79

Airplane start with initial speed

$v_i = 0$

now the takeoff velocity is given as

$v_f = 300 km/h$

$v_f = 83.33 m/s$

acceelration is given as

$a = 2 m/s^2$

now we have

$v_f - v_i = at$

from above equation we have

$83.33 - 0 = 2(t)$

$t = 41.7 s$

6 0

3 years ago

Use Kepler’s third law and the orbital motion of Earth to determine the mass of the Sun. The average distance between Earth and

Anna11 [10]

Kepler’s third law formula: T^2=4pi^2*r^3/(GM)

We’re trying to find M, so:

M=4pi^2*r^3/(G*T^2)

M=4pi^2*(1.496 × 10^11 m)^3/((6.674× 10^-11N*m^2/kg^2)*(365.26days)^2)

M=1.48× 10^40(m^3)/((N*m^2/kg^2)*days^2))

Let’s work with the units:

(m^3)/((N*m^2/kg^2)*days^2))=

=(m^3*kg^2)/(N*m^2*days^2)

=(m*kg^2)/(N*days^2)

=(m*kg^2)/((kg*m/s^2)*days^2)

=(kg)/(days^2/s^2)

=(kg*s^2)/(days^2)

So:

M=1.48× 10^40(kg*s^2)/(days^2)

Now we need to convert days to seconds in order to cancel them:

1 day=24 hours=24*60minutes=24*60*60s=86400s

M=1.48× 10^40(kg*s^2)/((86400s)^2)

M=1.48× 10^40(kg*s^2)/( 86400^2*s^2)

M=1.48× 10^40kg/86400^2

M=1.98x10^30kg

The closest answer is 1.99 × 10^30

(it may vary a little with rounding – the difference is less than 1%)

5 0

3 years ago

Read 2 more answers

In terms of energy, think about what happens when you eat a hot meal. Describe all the different forms of energy that you experi

vfiekz [6]

<span>The blackbody radiation of hot food can be felt on the skin in addition to the convective heat over the food. The thermal energy of the food can be felt through conductive heat when the food is touched, either by the hand or the mouth. The chemical energy in the food will be transferred to your body through the digestive system.</span>

3 0

3 years ago

Is baking a cake conduction, convection, or radiation?

Stolb23 [73]

Answer:

baking- is a method of cooking food that uses prolonged dry heat, normally in an oven, but also in hot ashes, or on hot stones. The primary source of heat is radiation. Fans within the oven will increase cooking times via convection of the air.

5 0

2 years ago