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miskamm [114]
3 years ago
10

Mathematically speaking, the energy of a wave is directionally proportional to the square of the amplitude of the wave Calculate

the energy of a wave that has an amplitude of 4 units A)1.0 B)2.0 C)4.0 D)160
Physics
2 answers:
evablogger [386]3 years ago
7 0

Answer:

Yes the answer is D

Explanation:

Because im batman

kenny6666 [7]3 years ago
6 0

The energy of the wave is D) 16.0 units squared

Explanation:

The energy of a wave is directly proportional to the square of the amplitude of the wave.

Mathematically, this can be written as

E\propto A^2

where

E is the energy of the wave

A is its amplitude

For the wave in this problem, the amplitude is

A = 4 units

Therefore, assuming that the constant of proportionality is 1, the energy of this wave is

E=A^2=4^2=16 units squared

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

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vazorg [7]
The boy’s foot causes the motion. His foot is the one that causes the ball to roll down the hill.
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Explian the construction of electric motor?​
Nataly_w [17]

Answer:

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7 0
3 years ago
A 2.2 kg model rocket is shot straight up in the air from the ground, with an initial velocity of 36.4 m/s. The rocket reaches i
alexandr1967 [171]

Answer:

Explanation:

Ignoring friction, the initial kinetic energy will convert to maximum potential energy at its highest point.

PE = KE

mgh = ½mv²

    h = v²/2g

    h = 36.4²/ (2(9.81))

    h = 67.53109...

    h = 67.53 m

3 0
2 years ago
How do u work out weight c and d and what r the answers
Ket [755]
The whole secret of things that are balanced on a pivot like this is:

The sum of all of the 'moments' is equal on both sides.

The moment of each weight is  (the weight) times (its distance from the pivot). 
If you add up those for each eight on one side, it has to be equal to the sum
of all the ones on the other side.

<u>2. a).</u> 
The moments on the right side are:  (4 x 0.15) and (1 x 0.40).
They add up to  (0.60 + 0.40) = 1.00

The only moment on the left side is  (C x 0.25).  Both sides have to be equal.

C x 0.25 = 1.00

Divide each side by 0.25, and you have    C = 4 N .

===========================================

<u>2. b).</u>
The only moment on the left side is  (5 x 0.40) = 2.00

The moments on the right side are (1 x 0.20) and (D x 0.30)
They add up to  (0.3D + 0.2).

Both sides have to be equal.    0.3D + 0.2 = 2.0

Subtract 0.2 from each side:      0.3D  =  1.8

Divide each side by 0.3:                D = 6 N
6 0
3 years ago
The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and
Kruka [31]

The strength of the electric field will be 215760 NC⁻¹. The concept of the electric field strength is used in the problem.

<h3>What is electric file strength?</h3>

The electric field strength is defined as the ratio of electric force and charge. Its unit is NC⁻¹.

The given data in the problem is;

E is the Electric Field Strength

k is the Colomb's constant = 8.99 x 10⁹ N.m²/C²

q is the magnitude of charge = 6 μC = 6 x 10⁻⁶ C

r is the distance = 0.5 m

The electric field strength is given by the formula;

\rm E = \frac{Kq}{R^2} \\\\ \rm E = \frac{8 .99 \times 10^9 6 \times 10^6 }{(0.5)^2} \\\\ E=215760 \ NC^{-1}

Hence the strength of the electric field will be 215760 NC⁻¹.

To learn more about the electric field strength refer to the link;

brainly.com/question/4264413

6 0
2 years ago
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