(Y+40)+(x+2y)=180
3y+x=140
2x+(y+20)=180
2x+y=160
Simultaneous equation
3y+x=140
Y+2x=160
Solve for y
Y=24
3(24)+x=140
X=140-72=68
not sure about the answer
Move the decimal 2 places to the right
8.4 becomes 840
Answer:
160
80
40
20
Step-by-step explanation:
You start with the first term that is given which would be
b(1)=<u><em>160</em></u>
That would be our first term, then we multiply by 0.5 which would be 1/2
which gives us 80 as it is a division
You take the next term that we have found (80) and then we do the same thing, multiply by 0.5 (1/2)
The original answer should be 48/100.
Reduced is 24/50
Even more is 12/25
Your answer is 12/25
First, tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>), so if cos(<em>θ</em>) = 3/5 > 0 and tan(<em>θ</em>) < 0, then it follows that sin(<em>θ</em>) < 0.
Recall the Pythagorean identity:
sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1
Then
sin(<em>θ</em>) = -√(1 - cos²(<em>θ</em>)) = -4/5
and so
tan(<em>θ</em>) = (-4/5) / (3/5) = -4/3
The remaining trig ratios are just reciprocals of the ones found already:
sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/3
csc(<em>θ</em>) = 1/sin(<em>θ</em>) = -5/4
cot(<em>θ</em>) = 1/tan(<em>θ</em>) = -3/4