Question

Four solid, uniform, cylindrical flywheels, each of mass 65.0 kg and radius 1.48 m rotate independently around a common axis. Three of the flywheels rotate in one direction at 7.84 rad/s ; the other rotates in the opposite direction at 3.42 rad/s. Calculate the magnitude of the net angular momentum of the system.

Answer 1

Answer:

L = 1430.88 kg m²/s

Explanation:

given,

mass of each flywheel = 65 Kg

radius of the rotation = 1.48

three fly wheel rotate in similar direction with speed = 7.84 rad/s

and another in opposite direction = 3.42 rad/s

net angular acceleration momentum = ?

we know,

$I = \dfrac{1}{2}MR^2$

I is moment of inertia

$I = \dfrac{1}{2}\times 65\times 1.48^2$

I = 71.188 kg.m²

angular momentum

L = I ω

three are in same direction and 1 is in different direction

L = 3 I ω₁ - I ω₂

L = 3 x 71.188 x 7.84 - 71.188 x 3.42

L = 1430.88 kg m²/s