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Nataliya [291]
4 years ago
14

You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 1515 lb and was trav

eling eastward. Car B weighs 1125 lb and was traveling westward at 43.0 mph. The cars locked bumpers and slid eastward with their wheels locked for 17.5 ft before stopping. You have measured the coefficient of kinetic friction between the tires and the pavement to be 0.750. How fast (in miles per hour) was car A traveling just before the collision? (This problem uses English units because they would be used in a U.S. legal proceeding.)
Physics
1 answer:
serious [3.7K]4 years ago
6 0

what was the speed limit, and it was 40 mph


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Differences between plastic and metal​
beks73 [17]

Answer:

Differences are listed below:

Explanation:

Weight: Plastic can weigh appreciably much less than than metal.A plastic part weighs approximately one-sixth of the same part in steel.

Chemical resistance:Plastic are much less likely to suffer chemical attack and don not corrode.

Machinability: Plastic are much more easier to cut through than metal.

Product life: The life span for plastic is longer than of the metals in many applications.

Cost: The cost of plastic raw materials is appreciably less than of the metals.

Heat: Plastic are less heat resistive than metals.

Ultraviolet light can degrade the plastics soon.

Strength: Metal provides more strength than the plastic.

6 0
3 years ago
a net force of 100 newton’s is a moving mass with an acceleration of 5 m/s. what is the mass of the object?
Jlenok [28]

F = ma

100 N= m . 5 ms⁻¹

100 / 5 = m

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7 0
3 years ago
What is the mass of a football player if they are running at 3.6 m/s with a momentum of 62.5kgm/s?
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62.5 = mass * 3.6

mass = 62.5/3.6

mass = 17.36 kg

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4 years ago
The instantaneous expression for the magnetic field intensity of a uniform plane wave propagating in the +y direction in air is
Alexxx [7]

Answer:

Explanation:

check attachment below for explicit explanation and answer.

3 0
3 years ago
Calculate the electric field on the surface of a charged sphere with a radius of 5cm and charge 10μC. Thanks
victus00 [196]

As you approach the surface of the sphere very closely, the electric field should resemble more and more the electric field from an infinite plane of charge.

If you check Gauss's law (recalling that the field in the conductor is zero) you will see that if the surface charge density is σ=Q/4πR2, then indeed the field at the surface is σ/ϵ0 as in the infinite charge of plane case.

Such a field is constant, the field lines are parallel and non-diverging, and the infinities associated with the field due to point charge do not arise.

Explanation:

4 0
2 years ago
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