Answer:
a) 86 atm
b) 86 atm
c) 645 m/s
Explanation:
See attachment for calculations on how i arrived at the answer
Answer:
a) E = 2.30×10^6N/C
Direction =+E . It will point radically outward
b)E = -3.3×10^5NC^-1
Direction =- E,it will point radically inwards
Explanation:
Magnitude E at 4.7cm= 0.047m
E= wavelength 1/2×3.142×rEo
E= (6.0×10^-6)/2×3.142×0.047×(8.85×10^-12)
E= (6.0×10^-6)/(2.6×10^-12)
E= 2.30×10^6N/C
Direction= +E shows it will point radically outward.
b) Magnitude E at 8.1cm=0.081
E= (wavelength 1+ wavelength 2) / 2×3.142rEo
E= [(6.0×10^-6)-(7.5×10^-6)]/(2×3.142×0.081×(8.84×10^-12)
E= -(1.5×10^-6)/(4.5×10^-11)
E= -3.3×10^5N/C
Direction =I-A it will point inwards
<1, 2, 3> x (7.6 <-5.3, -4.8, -3.9>) x stands for cross product
What does the above notation mean?
Multiply 7.6 to each component of the velocity vector to obtain the linear momentum vector. Find the cross product of the position vector and the linear momentum vector. That gives you the angular momentum vector.
7.6 * -5.3 = -40.28
7.6 * -4.8 = -36.48
7.6 * -3.9 = -29.64
Cross Multiplication
-40.28 1 = -80.56 - (-36.48)
-36.48 2
-40.28 1 = -120.84 - (-29.64)
-29.64 3
-36.48 2 = -109.44 - (-59.28)
-29.64 3
answer is (-91.2) - (50.16) + 117.04 = -24.32
Answer:
Average acceleration of the car is 1.167 m/s^2
Explanation:
The speed of car with which it is travelling is 12 m/s
As the driver accelerates the car, the speed reaches 26 m/s
The change in speed in 12 seconds is
26 -12 = 14 m/s
Average acceleration is change in speed divided by time
m/s^2