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3 years ago

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A charge of 9.0 × 10^–5 C is placed in an electric field with a strength of 2.0 × 10^4 N/C. What is the electrical force acting

on the charge?
a) What is given?
b) What are you asked to find?
c) What equation should you use?
d) What is the solution?

please help

1 answer:

Tresset [83]3 years ago

7 0

Answer: the force = 1.8N

check the pic for explanation

Explanation:

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the wavelength of helium-neon laser light in air is 721.4 nm

the frequency of helium-neon laser light in air is 415.86 THz

(b) the speed of helium-neon laser light in water is 2.26 x 10⁸ m/s

the wavelength of helium-neon laser light in water is 542.4nm

the frequency of helium-neon laser light in water is 416.67THz

(c) the speed of helium-neon laser light in glass is 2 x 10⁸ m/s

the wavelength of helium-neon laser light in glass is 480.9nm

the frequency of helium-neon laser light in glass is 415.88THz

From the results above, it can be seen that speed of the light is directly proportional to its wavelength, while the frequency of the light remained fairly constant for the different media.

Explanation:

Part (a) the speed, wavelength, and frequency of helium-neon laser light in air

Given;

wavelength of helium-neon laser light in air, λ = 721.4 nm

speed of light in air, v = 3 x 10⁸ m/s

v = f λ

where;

f is the frequency of helium-neon laser light in air

$f = \frac{v}{\lambda} = \frac{3*10^8}{721.4 *10^{-9}} =4.1586*10^{14} \ Hz$

f = 415.86 THz

Part (b) the speed, wavelength, and frequency of helium-neon laser light in water

refractive index of water = 1.33

$Refractive \ index \ of \ water =\frac{speed \ of \ light \ in \ air}{speed \ of \ light \ in \ water} = \frac{wavelength \ of \ light \ in \ air}{wavelength \ of \ light \ in \ water}$

$speed \ of \ light \ in \ water = \frac{speed \ of \ light \ in \ air}{Refractive \ index \ of \ water} \\\\speed \ of \ light \ in \ water = \frac{3*10^8}{1.33} = 2.26 *10^8 \ m/s$

Again;

$wavelength \ of \ light \ in \ water = \frac{wavelength \ of \ light \ in \ air}{Refractive \ index \ of \ water} \\\\wavelength \ of \ light \ in \ water = \frac{721.4 \ nm}{1.33} = 542.4 \ nm$

$f = \frac{v}{\lambda} = \frac{2.26*10^8}{542.4 *10^{-9}} =4.1667*10^{14} \ Hz$

f = 416.67 THz

Part (c) the speed, wavelength, and frequency of helium-neon laser light in glass

Refractive index of glass = 1.5

$speed \ of \ light \ in \ glass = \frac{speed \ of \ light \ in \ air}{Refractive \ index \ of \ glass} \\\\speed \ of \ light \ in \ glass = \frac{3*10^8}{1.5} = 2 *10^8 \ m/s$

Also;

$wavelength \ of \ light \ in \ glass = \frac{wavelength \ of \ light \ in \ air}{Refractive \ index \ of \ glass} \\\\wavelength \ of \ light \ in \ glass = \frac{721.4 \ nm }{1.5} = 480.9 \ nm$

$f = \frac{v}{\lambda} = \frac{2*10^8}{480.9 *10^{-9}} =4.1588*10^{14} \ Hz$

f = 415.88 THz

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