Answer:
mainly metal oxide use to react with both acid and bases to form salts such as zinc, aluminum etc.
PbS partially dissociates into ions as Pb²⁺ and S²⁻ in water. The balanced reaction is
PbS(s) ⇄ Pb²⁺(aq) + S²⁻(aq)
In the saturated solution, the reaction is at equilibrium.
Let's assume that solubility of PbS in saturated solution is "X".
Then according to the stoichiometry,
solubility of PbS = equilibrium concentration of Pb²⁺(aq) = equilibrium concentration of S²⁻(aq) = X
Ksp = [Pb²⁺(aq) ][S²⁻(aq)]
Ksp = X * X
3.0 × 10⁻²⁸ = X²
X = 1.7 x 10⁻¹⁴ M.
Hence the concentration of lead(ii) ions in a saturated solution of PbS is 1.7 x 10⁻¹⁴ M.
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Answer:
(1) 25.0cal/g (2) 540cal/g (3) 327 cal/g (4) 8,180 cal/g 82 If 11 grams of a gas occupies 5.6 liters at STP, what is its gram molecular mass? (1) 11 g/mol (2) 22 g/mol
Answer:
B
Explanation:
Noble gases are in group 18 (neon, argon, etc)
