Question

A gas has a volume of 800.0 mL at -23.0 degrees Celsius and 300.0 torr. What would the volume of the gas be at 227.0 degrees Celsius and 600.0 torr of pressure?

Answer 1

Answer:

The volume would be 800mL and it shows that it is constant.

Explanation:

Given parameters:

Intial volume of gas V₁ = 800mL

Initial temperature T₁ = -23°C to Kelvin; we use K = °C + 273 = -23 + 273 =                                                          250K

Inital pressure P₁ = 300torr

Final temperature T₂ = 227°C to K = 227 + 273 = 500K

Final pressure P₂ = 600torr

Unknown parameter:

Final volume V₂ = ?

To solve this problem, we use the General gas law or the combined gas law where we assume that n=1, this gives:

             $\frac{P_{1} V_{1} }{T_{1} }$ =   $\frac{P_{2} V_{2} }{T_{2} }$

Since the unknown is V₂, we make it the subject of the formula:

                V₂ = $\frac{P_{1} V_{1} T_{2} }{P_{2} T_{1} }$

                V₂ = $\frac{300x800x500}{600x250}$

                V₂ = 800mL