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3 years ago

A parent swings a 13.5 kg child

Physics

1 answer:

solmaris [256]3 years ago

3 0

The speed of the child is 2.21 m/s

Explanation:

The child is moving in circular motion. First of all, we find its frequency of revolution, which is given by:

$f=\frac{N}{t}$

where

N = 11 is the number of revolutions

t = 25.4 s is the time elapsed

So,

$f=\frac{11}{25.4}=0.433 Hz$

Now we find the angular frequency, which is given by

$\omega = 2\pi f = 2\pi(0.433)=2.72 rad/s$

And now we can fidn the linear speed of the child, which is given by

$v=\omega r$

where

$\omega=2.72 rad/s$ is the angular frequency

r = 0.811 m is the radius of the circular trajectory

Substituting,

$v=(2.72)(0.811)=2.21 m/s$

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

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Muscular Endurance is the ability of a muscle to continue to perform without fatigue.

Art [367]

Answer:

True.

Explanation:

Defenintion of Muscular Endurance:

The ability of a muscle (or set of muscles) to perform a repeated action without tiring.

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3 years ago

A small object with momentum 7.0 kg∙m/s approaches head-on a large object at rest. The small object bounces straight back with a

EastWind [94]

Answer:

The magnitude of the large object's momentum change is 3 kilogram-meters per second.

Explanation:

Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:

$p_{S,1}+p_{B,1} = p_{S,2}+p_{B,2}$ (1)

Where:

$p_{S,1}$ , $p_{S,2}$ - Initial and final momemtums of the small object, measured in kilogram-meters per second.

$p_{B,1}$ , $p_{B,2}$ - Initial and final momentums of the big object, measured in kilogram-meters per second.

If we know that $p_{S,1} = 7\,\frac{kg\cdot m}{s}$ , $p_{B,1} = 0\,\frac{kg\cdot m}{s}$ and $p_{S, 2} = 4\,\frac{kg\cdot m}{s}$ , then the final momentum of the big object is: