A parent swings a 13.5 kg child
1 answer:
The speed of the child is 2.21 m/s
Explanation:
The child is moving in circular motion. First of all, we find its frequency of revolution, which is given by:
where
N = 11 is the number of revolutions
t = 25.4 s is the time elapsed
So,
Now we find the angular frequency, which is given by
And now we can fidn the linear speed of the child, which is given by
where
is the angular frequency
r = 0.811 m is the radius of the circular trajectory
Substituting,
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Answer:
α = 2,857 10⁻⁵ ºC⁻¹
Explanation:
The thermal expansion of materials is described by the expression
ΔL = α Lo ΔT
α =
in the case of the bar the expansion is
ΔL = L_f - L₀
ΔL= 1.002 -1
ΔL = 0.002 m
the temperature variation is
ΔT = 100 - 30
ΔT = 70º C
we calculate
α = 0.002 / 1 70
α = 2,857 10⁻⁵ ºC⁻¹
Answer:
35.20 m
Explanation:
By the law of conservation of energy we have,
where m= mass of the skier, h= 3.00 m
D= horizontal distance=13.9 m
H= maximum height attained
Also, the horizontal distance covered by the skier is
D=vt
thus, height H in terms of D is given by
H=35.20 m