Question

A block slides down a frictionless inclined ramp. If the ramp angle is 17.0° and its length is 30.0 m, find the speed of the block as it reaches the bottom of the ramp, assuming it started sliding from rest at the top.

Answer 1

Answer:

 v = 17.15 m/s

Explanation:

given,

angle of ramp = 17.0°

length of ramp(l) = 30 m

height of the ramp =  

     $h = l sin \theta$

     $h = 30 sin 30^0$

            h = 15 m

using energy of conservation

$\dfrac{1}{2}mv^2 = mgh$

$\dfrac{1}{2}v^2 = gh$

$v = \sqrt{2gh}$

$v = \sqrt{2\times 9.8\times 15}$

$v = \sqrt{294}$

 v = 17.15 m/s

 speed of block reaching at the bottom = v = 17.15 m/s