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Serga [27]
3 years ago
12

At 7:00 pm the police discovered a body in a hotel room which maintained a constant temperature of 24 degree C. At the time of d

iscovery, the temperature of the dead body was 36 degree C. After 4 hours the temperature of the body fell to 30 degree C. Use Newton’s law of cooling to approximate the time of death. Using the formula:T – Tr = (To – Tr)e–t/tau
Physics
1 answer:
schepotkina [342]3 years ago
3 0

Explanation:

According to Newton's law of cooling,

T(t)=T_s+(T_o-T_s){e^{{-t/\tau}}

T(t) is the temperature at time t

T_s is temperature of surrounding

k=\dfrac{1}{\tau}

At the time of discovery, the temperature of the dead body was, T_o=36^{\circ}C

Temperature of the surrounding, T_s=24^{\circ}C

Temperature after 4 hours, T=30^{\circ}C

So, 30=24+(36-24)e^{-4t}

On solving the above equation,

k = 0.1735

Now, put the value of k in equation (1) at T = 36 degrees C

We know that, the temperature of body before death is T(t) = 37 degrees C

37=24+(36-24)e^{0.17t}

On solving above equation,

t = -0.46 hour

As time can't be negative and we have taken 7:00 pm as reference time.

So, t = 27.67 minutes

So, the death of the person is at 6 : 32 pm. Hence, this is the required solution.

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3 years ago
Tony drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took hours. When Tony drove hom
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Answer:

Question not completed, so I analysed the question first

Tony drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 6 hours. when tony drove home, there was no traffic and the trip only took 4 hours. if his average rate was 22 miles per hour faster on the trip home, how far away does tony live from the mountains?

Explanation:

Let use variables to solve the problems

Let the first trip to be mountain take x hours

Let the trip back home take y hours

Let the speed to while going to the mountain be a miles/hour

Then, while going home it was b miles/hour faster than while going to the mountain.

Then, speed going home is (a+b)miles / hour

The formula for speed is given as

Speed=distance/time

The constant through out the journey is distance, the two journey has the same distance.

Then,

Distance =speed×time

For first journey going to the mountain

Distance = a×x=ax miles

For the second journey going home

Distance =y×(a+b)

Distance Mountain= distance home

ax=y(a+b)

Make a subject of the formula

ax=ya+yb

ax-ya=yb

a(x-y)=yb

a=yb/(x-y)

Therefore, distance from mountain is

Distance=speed ×time

Distance= a×x=ax

Now, applying the questions

So from the questions

x=6hours, y=4hours

Also, b=22miles/hour

Then,

a=yb/(x-y)

a=4×22/(6-4)

a=88/2

a=44miles/hour

Then, the house distance from the mountain is

Distance=ax

Distance =44×6

Distance =264miles

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Answer:

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For this case we have that by definition, the momentum is given by:

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v = 1.5 \frac {m} {s}

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