When precipitation hits the surface of the ground and begins to

What is the pOH of a 0.150 M solution of potassium nitrite? (Ka HNO2 = 4.5 x 10−4 )

yanalaym [24]

Answer:

11.9 is the pOH of a 0.150 M solution of potassium nitrite.

Explanation:

Solution : Given,

Concentration (c) = 0.150 M

Acid dissociation constant = $k_a=4.5\times 10^{-4}$

The equilibrium reaction for dissociation of $HNO_2$ (weak acid) is,

$HNO_2+H_2O\rightleftharpoons NO_2^-+H_3O^+$

initially conc. c 0 0

At eqm. $c(1-\alpha)$ $c\alpha$ $c\alpha$

First we have to calculate the concentration of value of dissociation constant $(\alpha )$ .

Formula used :

$k_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}$

Now put all the given values in this formula ,we get the value of dissociation constant $(\alpha )$ .

$4.5\times 10^{-4}=\frac{(0.150\alpha)(0.150\alpha)}{0.150(1-\alpha)}$

$4.5\times 10^{-4} - 4.5\times 10^{-4}\alpha =0.150\alpha ^2$

$0.150\alpha ^2+4.5\times 10^{-4}\alpha-4.5\times 10^{-4}=0$

By solving the terms, we get

$\alpha=0.0533$

No we have to calculate the concentration of hydronium ion or hydrogen ion.

$[H^+]=c\alpha=0.150\times 0.0533=0.007995 M$

Now we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (0.007995 M)$

$pH=2.097\approx 2.1$

pH + pOH = 14

pOH =14 -2.1 = 11.9

Therefore, the pOH of the solution is 11.9

4 0

3 years ago

Convert 567 kg to grams

kodGreya [7K]

567000 would be in grams, hope this helps :)

8 0

2 years ago

Read 2 more answers

What is the energy for each question in Joules?

beks73 [17]

Answer:

Hello, there!

In order to solve problems like this DO PEMDAS

The Exponent:

So, equals 4

Your problem becomes

Now we have to do what is in the (

( the is a )

And

Problem becomes

So, this means that your answer would be

Good luck on your assignment and enjoy your day!

kjExplanation:

7 0

2 years ago

Show the relationship of number of moles and volume in Avogadro's law using data. Write your calculations and answer on a separa

leonid [27]

Answer:

See below ~

Explanation:

The calculated values of V/n :

⇒ 1.5/0.3 = 5

⇒ 3/0.6 = 5

⇒ 4.5/0.9 = 5

⇒ 6/1.2 = 5

⇒ 7.5/1.5 = 5

1. From this we understand that the calculated values of V/n remain constant, equal to <u>5</u> in this case.

2. The volume-mole graph will be a straight line passing through the origin. (Attached below)

7 0

1 year ago

What feature of single nucleotides provides the energy needed for polymerization when nucleic acids are formed?

lukranit [14]

When the phosphate groups of the single nucleotides combine to form the backbone of the nucleic acid, energy is released. This energy is used for polymerization.

4 0

2 years ago