<span>fast-moving particles colliding with slow-moving particles</span>
Answer: assuming that the billiard balls are of identical weight the impacted billiard ball will move forward at around 0.5m/s (not considering energy conservation). The ball impacting the 2nd one would stop because most of its Kinetic energy would have been transferred into the not moving ball.
Explanation: hope this helps!
When analyzing inelastic collisions, we need to consider the law of conservation of momentum, which states that the total momentum, p, of the closed system is a constant. In the case of inelastic collisions, the momentum of the combined mass after the collision is equal to the sum of the momentum of each of the initial masses.
p1+p2+...=pf
In our case we only have two masses, which makes our problem fairly simple. Lets plug in the formula for momentum; p=mv.
m1v1+m2v2=(m1+m2)vf
To find the velocity of the combined mass we simply rearrange the terms.
vf=m1v1+m2v2m1+m2
Plug in the values given in the problem.
vf=(3.0kg)(1.4m/s)+(2.0kg)(0m/s)03.0kg+2.0kg
vf=.84m/s
True. Their immune system weakens and they stay sick until they die.
If you stand on one side of a strike-slip fault and the block on the other side of the fault has moved to your left, this is known as a(n) left lateral fault.
There are several distinct sorts of fault lines, and they are called based on the fault's movement and the fault plane's own direction. These faults may be found all over the world, but the most active and earthquake-producing ones are in the Pacific Ocean's Ring of Fire region.
When you gaze along the length of a fault line, the left side will move toward you while the right side moves away from you. This is referred to as a left-lateral fault.
To know more about left lateral fault visit : brainly.com/question/14136640
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