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Lapatulllka [165]
3 years ago
8

Can you force the atoms into new configurations by pushing atoms around? What does this suggest about the configuration of atoms

in real molecules?
Chemistry
2 answers:
Temka [501]3 years ago
8 0
You can't because the electrons repel
slega [8]3 years ago
5 0

Answer:  No

Explanation:  No, we cannot force the atoms to leave their original shape and

gain a new configuration by pushing all the atoms because of the Repulsion Theory, which explains that no 2 electrons can be stay together in the minimum space because they would repel each other. That is why the lone pairs of electrons share the maximum space so that they wont be able to get in to the vicinity of the bonded electrons and thus experiencing the maximum repulsion.

Thus configuration of atoms in the real molecules suggests that the bonded pair of electrons and lone pairs of electrons (if present) will share the maximum space .

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What is the concentration of a solution formed by mixing 89.94 grams of cobalt (II)
bezimeni [28]

Answer:

0.47 M

Explanation:

The concentration of the solution can be calculated using the following equation:

C = \frac{\eta}{V} = \frac{m}{M*V}

<u>Where:</u>

V: is the volume of the solution = 68.6x10⁻² L

η: is the moles of cobalt (II)  sulfate

m: is the mass of cobalt (II)  sulfate = 89.94 g

M: is the molar mass of cobalt (II)  sulfate = 281.103 g/mol

The concentration of cobalt (II)  sulfate is:

C = \frac{m}{M*V} = \frac{89.94 g}{281.103 g/mol*68.6 \cdot 10^{-2} L} = 0.47 mol/L

We used the molar mass of the cobalt (II)  sulfate heptahydrate (281.103 g/mol) since it is one of the most common salts of cobalt.

Therefore, the concentration of a solution of cobalt (II)  sulfate is 0.47 M (assuming that the cobalt (II)  sulfate is heptahydrate).

I hope it helps you!

3 0
3 years ago
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Eugene describes the physical property of a material as “sweet and floral.” What physical property of the material is Eugene mos
nataly862011 [7]

Answer:

D

Explanation:

5 0
3 years ago
Ammonia is produced industrially via this exothermic reaction.
Cloud [144]

Answer:

high pressure of 200-300 atm.

low temp. of between 400-500 degrees celsius:this is for continuous development of ammonia since it decomposes at high temp fathermore the reaction is exothermic

a catalyst to speed up the rate of reaction:i guess it is finely divided iron impregnated in aluminium oxide

platinum can be used as a catalyst but it is easily poisoned

hope it helps

Explanation:

6 0
3 years ago
Technetium 99 releases a gamma ray
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what?? please reword this

6 0
3 years ago
Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

7 0
3 years ago
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